C ++无效使用成员函数(你忘了'()'吗?)

时间:2014-12-30 21:32:36

标签: c++ compiler-errors containers members

我无法编译程序。错误发生在第165-177行。我添加的只是对字母存在的测试,我收到了错误,希望你能帮忙! 完整代码http://pastebin.com/embed.php?i=WHrSasYk

(以下是代码)

do
{
  cout << "\nCustomer Details:";

  cout << "\n\tCustomer Name:";
  cout << "\n\t\tFirst Name:";
  getline (cin, Cust_FName, '\n');
  if (Quotation::Cust_FName.length() <= 1)
    ValidCustDetails = false;
  else
  {
    // Error line 165!
    for (unsigned short i = 0; i <= Cust_FName.length; i++)
      if (!isalpha(Quotation::Cust_FName.at(i)))
        ValidCustDetails = false;
  }
  cin.ignore();
  cout << "\t\tLast Name:";
  getline (cin, Cust_LName, '\n');
  if (Cust_LName.length () <= 1)
    ValidCustDetails = false;
  else
  {
    // Error line 177!
    for (unsigned short i = 0; i <= Cust_LName.length; i++)
      if (!isalpha(Cust_LName.at(i)))
        ValidCustDetails = false;
  }
  cin.ignore();
}
while(!ValidCustDetails);

2 个答案:

答案 0 :(得分:9)

这些问题是您的问题:

for (unsigned short i = 0; i <= Cust_FName.length; i++)
for (unsigned short i = 0; i <= Cust_LName.length; i++)
//                                              ^^

std::string::length是一个函数,因此您需要使用parens调用它:

for (unsigned short i = 0; i <= Cust_FName.length(); i++)
for (unsigned short i = 0; i <= Cust_LName.length(); i++)

答案 1 :(得分:2)

我怀疑Cust_LNamestd::string 所以你应该在()之后添加length

Cust_LName.length()