Question

我根据这个文件名有文件名。我需要找到文件的路径。如何根据文件名查找文件的路径？我需要根据文件名示例代码找到文件的路径：

string path=      System.IO.Directory.GetDirectories(@"c:\", "kategori",System.IO.SearchOption.AllDirectories).First();

但我需要：

string path=      System.IO.Directory.GetDirectories(@"anyFolder", "kategori",System.IO.SearchOption.AllDirectories).First();

我需要


Main()
{
string path = PathFinder("Afilename")
}

output: C:\myFiles\AfileName

string PathFinder(string fileName)
{

..................

.................

........

.......

....

..

.

}

Answer 1

这样的功能可能适合你：

public static String SearchFileRecursive(String baseFolderPath, String fileName)
    {
        // Returns, if found, the full path of the file; otherwise returns null.
        var response = Path.Combine(baseFolderPath, fileName);
        if (File.Exists(response))
        {
            return response;
        }

        // Recursion.
        var directories = Directory.GetDirectories(baseFolderPath);
        for (var i = 0; i < directories.Length; i++)
        {
            response = SearchFileRecursive(directories[i], fileName);
            if (response != null) return response;
        }

        // { file was not found }

        return null;
    }

Answer 2

http://support.microsoft.com/kb/303974

Answer 3

我想要更多LINQish方式：

public static IEnumerable<FileInfo> FindFile(string fileName)
{
    if (String.IsNullOrEmpty(fileName))
        throw new ArgumentException("fileName");

    return Directory.GetLogicalDrives()
                    .SelectMany(drive => FindFile(fileName, drive));
}

public static IEnumerable<FileInfo> FindFile(string fileName, string folderName)
{
    if (String.IsNullOrEmpty(fileName))
        throw new ArgumentException("fileName");
    if (String.IsNullOrEmpty(fileName))
        throw new ArgumentException("folderName");

    var matchingFiles = Directory.EnumerateFiles(folderName)
                                 .Where(file => Path.GetFileName(file) == fileName)
                                 .Select(file => new FileInfo(file));

    var matchingFilesFromSubDirs = Directory.EnumerateDirectories(folderName)
                                            .SelectMany(directory => FindFile(fileName, directory));

    return matchingFiles.Concat(matchingFilesFromSubDirs);
}

可以用于：

foreach (var file in FindFile("myFile.ext"))
{
    Console.WriteLine("Name: " + file.FullName);
}

如何根据文件名查找文件的路径？

我需要

3 个答案: