我创建了一个C程序作为我今年在学校的最后一个项目,他们想让我创建一个学生数据库程序。在这里,工作几乎完美无瑕,但它不会正确注册身份证号码。
http://i.imgur.com/46fCxPc.png
在此图片上,您可以清楚地看到我输入了23915741843作为身份证号码,但它注册为; -1854061933。
我已经用了很长时间来修复它,但是没有。它不会真正起作用。我被允许从互联网上获取帮助。所以这是我的完整代码。它有什么问题?
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
struct
{
long int id;
char firstname[20];
char lastname[20];
int mark;
}student;
int main()
{
long int idnumber;
int flag,choice,shift,found,continu,length;
char studentname[20];
FILE *fp;
printf("\n\tC PROGRAM OF STUDENT DATABASE SYSTEM");
Label1:
printf("\n1 -> Store a new record in database\n");
printf("2 -> Search a student record by Student First Name\n");
printf("3 -> Search a student record by ID\n");
printf("4 -> Quit Student Database");
printf("\n\n");
printf("Enter your choice : ");
scanf("%d",&choice);
switch(choice)
{
case 1:
Label2:
printf("\nEnter Student Details:\n\nID number: ");
scanf("%d",&student.id);
printf("\nName:");
scanf("%s",student.firstname);
printf("\nSurname:");
scanf("%s",student.lastname);
printf("\nMark(0 - 100 integer) : ");
scanf("%d",&student.mark);
fp=fopen("studentfile.txt","a+");
fprintf(fp,"\n%d\t%s\t%s\t%d\t",student.id,student.firstname,student.lastname,student.mark);
fclose(fp);
printf("A student record has been added successfully...\n");
printf("\n\n1 -> Wish to add another record to database");
printf("\n2 -> Wish to move to Main Menu");
printf("\n3 -> Exit from Program\n");
scanf("%d",&shift);
if(shift==1)
goto Label2;
if(shift==2)
goto Label1;
if(shift==3)
break;
if(shift!=1&&2&&3){
printf("Exiting.........");
break;
}
case 2:
Label4:
printf("\nEnter student first name: ");
scanf("%s",&studentname);
printf("Searching record with studentname=%s.\n",studentname);
found=0;
if((fp=fopen("studentfile.txt","r"))==NULL)
{
printf(" ! The File is Empty...\n\n");
}
else
{
while(!feof(fp)&& found==0)
{
fscanf(fp,"\n%d\t%s\t%s\t%d\t",&student.id,student.firstname,student.lastname,&student.mark);
length = strlen(student.firstname);
if(student.firstname[length]==studentname[length])
found=1;
}
}
if(found)
{
printf("\nThe record is found.\n");
printf("\nID: %d\nName: %s\nSurname: %s\nMark: %d \n",student.id,student.firstname,student.lastname,student.mark);
}
else
{
printf("Not found...\n");
getch();
}
Label5:
printf("\n\n1 -> Wish to search another record");
printf("\n2 -> Wish to move to Main Menu");
printf("\n3 -> Exit from Program\n");
scanf("%d",&shift);
if(shift==1)
goto Label4;
if(shift==2)
goto Label1;
if(shift==3)
break;
if(shift!=1&&2&&3){
printf("\nEnter a valid choice");
goto Label5;
}
case 3:
Label6:
printf("\nEnter the ID: ");
scanf("%d",&idnumber);
printf("Searching record with ID=%d.\n",idnumber);
found=0;
if((fp=fopen("studentfile.txt","r"))==NULL)
{
printf(" ! The File is Empty...\n\n");
}
else
{
while(!feof(fp)&& found==0)
{
fscanf(fp,"\n%d\t%s\t%s\t%d\t",&student.id,student.firstname,student.lastname,&student.mark);
if(student.id==idnumber)
found=1;
}
}
if(found)
{
printf("\nThe record is found.");
printf("\nID no: %d\nName: %s\nSurname: %s\nMark: %d \n",student.id,student.firstname,student.lastname,student.mark);
}
else
{
printf("Not found...\n");
getch();
}
Label7:
printf("\n\n1 -> Wish to search more..");
printf("\n2 -> Wish to move to Main Menu");
printf("\n3 -> Exit from Program\n");
scanf("%d",&shift);
if(shift==1)
goto Label6;
if(shift==2)
goto Label1;
if(shift==3)
break;
if(shift!=1&&2&&3){
printf("\nEnter a valid choice");
goto Label7;
}
case 4: break;
default :
printf(" Bad choice...Enter the choice again...\n");
goto Label1;
}
getch();
return 0;
}
答案 0 :(得分:2)
TL; DR - &gt;请使用适当的格式说明符,并始终检查使用的数据类型可以保存的值的限制。
在您的代码中,
scanf("%d",&student.id);
%d
不是long int
的正确格式说明符。
long int
,它应为%ld
unsigned long int
,它应为%lu
此外,23915741843
是一个太大而无法被long int
占据的值。来自§5.2.4.2.1
的{{1}}
long int
类型的对象的最大值LONG_MAX +2147483647 // 2 31 - 1
您可以使用c99
[long long int
]。
旁注:您从未检查%lld
,fopen()
等是否成功。
答案 1 :(得分:0)
scanf("%ld",&student.id);
使用正确的格式说明符来扫描long int。 IMO id
将是无符号值,因此如果错误,请将id
设为unsinged long int id
,并使用%lu
扫描该值。如果没有,请确保该值符合允许的范围,然后使用long long int
并使用%lld
格式说明符进行相应扫描。
使用goto
时,您的代码看起来很混乱。请确保您已克服它。
显示您的提示并让切换案例相应地处理它。如果用户想要退出时有一个单独的案例并处理这种情况而不是使用goto