Question

我在PostgreSQL中有一个SQL表（3列：数字，数字，字符串） -

100226, 118, "{{5662,"IBM Certified for On Demand Business - Solution Advisor - 816"},{5663,"MS Windows XP Desktop Administration   -  Assessment - E1"},{5664,"MS Windows 95 Navigation   -  Assessment - E3"},{5671,"TestPrep Final Exam: Six Sigma Foundations"}"

现在我的要求是获取表格中的行，如下所示

100226    118    {5662,"IBM Certified for On Demand Business - Solution Advisor - 816"}
                 {5663,"MS Windows XP Desktop Administration   -  Assessment - E1"}
                 {5664,"MS Windows 95 Navigation   -  Assessment - E3"}
                 {5671,"TestPrep Final Exam: Six Sigma Foundations"}

以下是我正在检索值

的查询

select
    chs.lms_im_employee_id emp_num,
    chs.lms_mr_cp_id complaince_no,
    entity_name
from
    lms.lms_im_cmplnc_objtemp obj,
    lms.lms_im_cmplnc_history chs
where
    obj.lms_mr_cp_id=chs.lms_mr_cp_id
    and  obj.lms_im_employee_id = chs.lms_im_employee_id      
    and chs.lms_im_ch_is_compliant = false 
    and  chs.lms_im_employee_id  = '66'
group by chs.lms_mr_cp_id, chs.lms_im_employee_id;

Answer 1

首先，如果可能的话，存储你的字符串将是有益的，但如果没有，尝试以下

现在，您的数据看起来有点格式不正确，因为它缺少最终}。在这个答案中，我认为这是一个错误，如果不是，你将不得不清理你的数据，或者重写我的查询以在原始数据的末尾附加'}'。

select
    chs.lms_im_employee_id emp_num,
    chs.lms_mr_cp_id complaince_no,
    json_array_elements(array_to_json(entity_name::text[])) entity_name
from
    lms.lms_im_cmplnc_objtemp obj,
    lms.lms_im_cmplnc_history chs
where
    obj.lms_mr_cp_id=chs.lms_mr_cp_id
    and  obj.lms_im_employee_id = chs.lms_im_employee_id      
    and chs.lms_im_ch_is_compliant = false 
    and  chs.lms_im_employee_id  = '66'
group by chs.lms_mr_cp_id, chs.lms_im_employee_id;

或者，如果您的数据实际上缺少结束}

select
    chs.lms_im_employee_id emp_num,
    chs.lms_mr_cp_id complaince_no,
    json_array_elements(array_to_json((entity_name||'}')::text[])) entity_name
from
    lms.lms_im_cmplnc_objtemp obj,
    lms.lms_im_cmplnc_history chs
where
    obj.lms_mr_cp_id=chs.lms_mr_cp_id
    and  obj.lms_im_employee_id = chs.lms_im_employee_id      
    and chs.lms_im_ch_is_compliant = false 
    and  chs.lms_im_employee_id  = '66'
group by chs.lms_mr_cp_id, chs.lms_im_employee_id;

当然所有这些都假定您的数据格式完美。如果不是，那么您将不得不清理数据，或编写自定义函数来解释它。

SQL表中的deliminator列值

1 个答案: