Question

当满足两个条件时，我使用以下语句来摆脱循环：

while (true)
    {
        if (uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2)
                || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4) 
                &&
                uAnswer2.equals(answerS1)|| uAnswer2.equals(answerS2)){
            break;
        }

当一个或两个＆amp;＆amp;条件得到满足。但是，当两个条件都为真时，我编写了代码来打破循环。

上述陈述中是否缺少某些内容？问候， Shei7141。

Answer 1

将它们包装在括号中

if ( (uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2)
                || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4))
&&
(uAnswer2.equals(answerS1)|| uAnswer2.equals(answerS2)) )

或

即使提出HashSet正确的答案，这样做也会很干净，而且效率也很高

answers1Set.contains(uAnswer1) && answers2Set.contains(uAnswer2)

Answer 2

上面的代码显示 uAnswer1.equals（answerB4）＆amp;＆amp; uAnswer2.equals（answerS1）处于 AND 状态

while (true)
    {
        if ((uAnswer1.equals(answerB1) || uAnswer1.equals(answerB2)
                || uAnswer1.equals(answerB3)|| uAnswer1.equals(answerB4)) 

                &&

                (uAnswer2.equals(answerS1)|| uAnswer2.equals(answerS2))){
            break;
        }

Answer 3

while（true） { if（（uAnswer1.equals（answerB1）|| uAnswer1.equals（answerB2） || uAnswer1.equals（answerB3）|| uAnswer1.equals（answerB4））＆安培;＆安培; （uAnswer2.equals（answerS1）|| uAnswer2.equals（answerS2）））打破; }

Java和和或运算符不工作

3 个答案: