Question

我是第一次尝试使用python在OOP中编写。它仍然没有感觉通过主控制器传递接口类型。我试图遵循SOLID原则。让我展示代码。

TicTacToeOnConsol.py：

import os
from Controller import StartController

os.system('cls')
StartController().StartGame('consolInterface')

Controller.py：

from UserInterface import ExecuteActionOnInterface

class StartController:
    def StartGame(self, strInterfaceType):
        dispWelcomeContinue = ExecuteActionOnInterface().DisplayWelcome(strInterfaceType)
        if dispWelcomeContinue == False:
            return False
        #Do more stuff
        return True

UserInterface.py：

from ConsolInterface import ConsolInputMessages
from ConsolInterface import ConsolOutputMessages

class ExecuteActionOnInterface:
    def __init__(self):
        self.selectDisplayWelcome = {
            'consolInterface' : ConsolInterface().DisplayWelcomeConsol,
            'windowInterface' : WindowInterface().DisplayWelcomeWindow,
            'webInterface' : WebInterface().DisplayWelcomeWeb,
        }
    def DisplayWelcome(self, strInterfaceType):
        self.selectDisplayWelcome[strInterfaceType]()
        return True

class ConsolInterface:
    def DisplayWelcomeConsol(self):
        return ConsolInputMessages().DisplayWelcomeWithInput()

class WindowInterface:
    def DisplayWelcomeWindow(self):
        raise NotImplementedError('This interface has not yet been implemented')

class WebInterface:
    def DisplayWelcomeWeb(self):
        raise NotImplementedError('This interface has not yet been implemented')

ConsolInterface.py：

import os
import msvcrt as inputKey

class ConsolInputMessages:
    def ContinueOrQuit(self):
        print "Any Key = Continue"
        print "Q = Quit"
        print "Please press Any Key to continue, or Q to quit:"
        continueOrQuit = inputKey.getche().upper()
        if continueOrQuit == 'Q':
            print '\n'
            print '\nExiting Game...'
            return 'quit'
        os.system('cls')
        return 'continue'

    def ContinueRestartOrQuit(self):
        print "Any Key = Continue"
        print "Q = Quit"
        print "R = Restart"
        print "Please press Any Key to continue, R to restart, or Q to quit:"
        continueRestartOrQuit = inputKey.getche().upper()
        if continueRestartOrQuit == 'Q':
            print '\n'
            print '\nExiting Game...'
            return 'quit'
        elif continueRestartOrQuit == 'R':
            print '\n'
            print '\nRestating Game...'
            return 'restart'
        os.system('cls')
        return 'continue'

    def DisplayWelcomeWithInput(self):
        ConsolOutputMessages().DisplayWelcome()
        if self.ContinueOrQuit() == 'quit':
            return False
        return True


class ConsolOutputMessages:
    def DisplayWelcome(self):
        print """\
******************************************************
**************** Welcome to TicTacToe ****************
******************************************************
Copyright (c) 2014 fiddlefreak
All Rights Reserved

This product is protected by copyright and distributed under
licenses restricting copying, distribution and decompilation.
"""

任何python专家都能给我一些例子，说明UserInterface如何将Consol接口实例化为自己的对象，所以当控制器在接口上调用一个函数时，它不必通过通过类型，UserInterface已经知道使用哪一个？

Answer 1

不传递接口类型的字符串值，传递类的实例（或传递字符串，并让控制器实例化接口）。您可以在创建控制器时执行此操作。保存对接口的引用，然后直接调用该接口上的方法：

interface = ConsoleInterface()
StartController(interface).StartGame()
...
class StartController:
    def __init__(self, interface):
        self.interface = interface

    def StartGame(self, interface):
        self.interface.DisplayWelcome()
        return True

Python - 如何使用适配器接口

1 个答案: