我在Hibernate和Spring开发方面绝对是新的，我有以下问题
我有一个名为KM_ProjectInfoStatus的实体类映射名为KM_PROJECT_INFO_STATUS的数据库表，所以我有这个类：
package egp.prc.km.model;
import javax.persistence.*;
import java.io.Serializable;
@NamedQueries({
@NamedQuery(name = "kmProjectInfoStatusList", query = "select status from KM_PROJECT_INFO_STATUS status order by status.idProjectInfoStatus") ,
@NamedQuery(name = "kmProjectInfoStatusById", query = "SELECT status FROM KM_PROJECT_INFO_STATUS status where lower(status.idProjectInfoStatus) = :statusId")
})
@Entity
@Table(name = "KM_PROJECT_INFO_STATUS")
public class KM_ProjectInfoStatus implements Serializable {
@Id
@GeneratedValue
private Long idProjectInfoStatus;
@Column(name = "foldertech")
private Long foldertech;
@Column(name = "folderproject")
private Long folderproject;
public Long getIdProjectInfoStatus() {
return idProjectInfoStatus;
}
public void setIdProjectInfoStatus(Long idProjectInfoStatus) {
this.idProjectInfoStatus = idProjectInfoStatus;
}
public Long getFoldertech() {
return foldertech;
}
public void setFoldertech(Long foldertech) {
this.foldertech = foldertech;
}
public Long getFolderproject() {
return folderproject;
}
public void setFolderproject(Long folderproject) {
this.folderproject = folderproject;
}
}
正如您在上一个代码段中看到的那样，该类定义了2个命名查询，这些：
@NamedQueries({
@NamedQuery(name = "kmProjectInfoStatusList", query = "select status from KM_PROJECT_INFO_STATUS status order by status.idProjectInfoStatus") ,
@NamedQuery(name = "kmProjectInfoStatusById", query = "SELECT status FROM KM_PROJECT_INFO_STATUS status where lower(status.idProjectInfoStatus) = :statusId")
})
1）第一个名为 kmProjectInfoStatusList ，并从我的 KM_PROJECT_INFO_STATUS 表格中选择行列表。
2）第二个名为 kmProjectInfoStatusById ，并使用where条件中的id从我的 KM_PROJECT_INFO_STATUS 表中选择一行。
然后我必须实现一个实现DAO的Spring服务。
所以我首先创建一个名为 KMProjectInfoStatusService 的接口，其中我声明了我的DAO的方法：
public interface KMProjectInfoStatusService {
@Transactional
public List<KM_ProjectInfoStatus> getProjectInfoStatusList();
@Transactional
public KM_ProjectInfoStatus getProjectInfoStatus(Long idProjectInfoStatus);
}
我在Hibernate和Spring开发方面绝对是新的，我有以下问题
我有一个名为KM_ProjectInfoStatus的实体类映射名为KM_PROJECT_INFO_STATUS的数据库表，所以我有这个类：
package egp.prc.km.model;
import javax.persistence.*;
import java.io.Serializable;
@NamedQueries({
@NamedQuery(name = "kmProjectInfoStatusList", query = "select status from KM_PROJECT_INFO_STATUS status order by status.name") ,
@NamedQuery(name = "kmProjectInfoStatusById", query = "SELECT status FROM KM_PROJECT_INFO_STATUS status where lower(status.idProjectInfoStatus) = :statusId")
})
@Entity
@Table(name = "KM_PROJECT_INFO_STATUS")
public class KM_ProjectInfoStatus implements Serializable {
@Id
@GeneratedValue
private Long idProjectInfoStatus;
@Column(name = "foldertech")
private Long foldertech;
@Column(name = "folderproject")
private Long folderproject;
public Long getIdProjectInfoStatus() {
return idProjectInfoStatus;
}
public void setIdProjectInfoStatus(Long idProjectInfoStatus) {
this.idProjectInfoStatus = idProjectInfoStatus;
}
public Long getFoldertech() {
return foldertech;
}
public void setFoldertech(Long foldertech) {
this.foldertech = foldertech;
}
public Long getFolderproject() {
return folderproject;
}
public void setFolderproject(Long folderproject) {
this.folderproject = folderproject;
}
}
正如您在上一个代码段中所看到的，该类还包含2个命名查询，这些查询：
@NamedQueries({
@NamedQuery(name = "kmProjectInfoStatusList", query = "select status from KM_PROJECT_INFO_STATUS status order by status.name") ,
@NamedQuery(name = "kmProjectInfoStatusById", query = "SELECT status FROM KM_PROJECT_INFO_STATUS status where lower(status.idProjectInfoStatus) = :statusId")
})
然后我必须实现一个实现DAO的Spring服务。
所以我首先创建一个名为KMProjectInfoStatusService的接口，在其中我声明了我的DAO的方法：
public interface KMProjectInfoStatusService {
@Transactional
public List<KM_ProjectInfoStatus> getProjectInfoStatusList();
@Transactional
public KM_ProjectInfoStatus getProjectInfoStatus(Long idProjectInfoStatus);
}
最后，我创建了 KMProjectInfoStatusServiceImp 类，它实现了以前的接口，代表了我的具体DAO：
@Repository("kmProjectInfoStatusService")
public class KMProjectInfoStatusServiceImpl extends AbstractService implements KMProjectInfoStatusService {
public List<KM_ProjectInfoStatus> getProjectInfoStatusList() {
//return new KM_ProjectInfoStatus[0]; //To change body of implemented methods use File | Settings | File Templates.
return getHibernateTemplate().execute(
new HibernateCallback<List<KM_ProjectInfoStatus>>() {
public List<KM_ProjectInfoStatus> doInHibernate(Session session) throws HibernateException, SQLException {
return getStatusList(session);
}
}
);
}
public KM_ProjectInfoStatus getProjectInfoStatus(Long idProjectInfoStatus) {
//return null; //To change body of implemented methods use File | Settings | File Templates.
final Long id = idProjectInfoStatus;
return getHibernateTemplate().execute(
new HibernateCallback<KM_ProjectInfoStatus>() {
public KM_ProjectInfoStatus doInHibernate(Session session) throws HibernateException, SQLException {
return getStatus(id, session);
}
}
);
}
private List<KM_ProjectInfoStatus> getStatusList(Session session) {
//create query:
Query query = session.getNamedQuery("kmProjectInfoStatusList");
List<KM_ProjectInfoStatus> statusList = query.list();
return statusList;
}
private KM_ProjectInfoStatus getStatus(Long idProjectInfoStatus, Session session) {
//create query:
Query query = session.getNamedQuery("kmProjectInfoStatusById");
query.setParameter("statusId", idProjectInfoStatus);
KM_ProjectInfoStatus status = (KM_ProjectInfoStatus) query.uniqueResult();
return status;
}
}
正如您在本课程中看到的，我实现了在接口中声明的2个方法 getProjectInfoStatusList（）和 getProjectInfoStatus（）。这两种方法分别使用 getStatusList（）来执行第一个命名查询以获取列表，使用 getStatus（）执行第二个查询以从其id获取对象。
问题是，当我尝试执行我的项目时， HibernateException 是throwns，我在stacktrace中获得以下错误消息：
2014-12-29 16:25:44,210 [[ACTIVE] ExecuteThread: '2' for queue: 'weblogic.kernel.Default (self-tuning)'] ERROR impl.SessionFactoryImpl.<init>(363) - Error in named query: kmProjectInfoStatusById
org.hibernate.hql.ast.QuerySyntaxException: KM_PROJECT_INFO_STATUS is not mapped [SELECT status FROM KM_PROJECT_INFO_STATUS status where lower(status.idProjectInfoStatus) = :statusId]
at org.hibernate.hql.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:158)
at org.hibernate.hql.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:87)
at org.hibernate.hql.ast.tree.FromClause.addFromElement(FromClause.java:70)
at org.hibernate.hql.ast.HqlSqlWalker.createFromElement(HqlSqlWalker.java:255)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3056)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:2945)
................................................................................
................................................................................
................................................................................
................................................................................
<29-dic-2014 16.25.44 CET> <Error> <Deployer> <BEA-149202> <Encountered an exception while attempting to commit the 1 task for the application 'KM_Web_war_exploded'.>
<29-dic-2014 16.25.44 CET> <Warning> <Deployer> <BEA-149004> <Failures were detected while initiating deploy task for application 'KM_Web_war_exploded'.>
<29-dic-2014 16.25.44 CET> <Warning> <Deployer> <BEA-149078> <Stack trace for message 149004
weblogic.application.ModuleException: :org.hibernate.HibernateException:Errors in named queries: kmProjectInfoStatusById, kmProjectInfoStatusList
at org.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:365)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1300)
at org.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:859)
at org.springframework.orm.hibernate3.LocalSessionFactoryBean.newSessionFactory(LocalSessionFactoryBean.java:860)
at org.springframework.orm.hibernate3.LocalSessionFactoryBean.buildSessionFactory(LocalSessionFactoryBean.java:779)
Truncated. see log file for complete stacktrace
为什么呢？可能是什么问题呢？我错过了什么？我该如何解决这个问题？
答案 0 :(得分：2)
你在Hibernate世界中，所以你需要使用Hibernate实体名称而不再使用SQL表名。默认情况下，实体名称是类的简单名称。
所以你应该写一些类似的东西：
select status from KM_ProjectInfoStatus status order by status.name
Google有关HQL / JPQL的更多信息，请参阅详细信息。
答案 1 :(得分：1)
HQL需要classname和SQL需要表名
在您的HQL中使用KM_ProjectInfoStatus而不是KM_PROJECT_INFO_STATUS。
@NamedQueries({
@NamedQuery(name = "kmProjectInfoStatusList", query = "select status from KM_ProjectInfoStatus status order by status.name") ,
@NamedQuery(name = "kmProjectInfoStatusById", query = "SELECT status FROM KM_ProjectInfoStatus status where lower(status.idProjectInfoStatus) = :statusId")
})
HQL thus should not use table names, but entity class names
答案 2 :(得分：1)
这应该是HQL查询（而不是SQL）：
SELECT status FROM KM_PROJECT_INFO_STATUS status where lower(status.idProjectInfoStatus) = :statusId
所以你不应该使用表名（KM_PROJECT_INFO_STATUS），而是使用实体类名（KM_ProjectInfoStatus），如下所示：
SELECT status FROM KM_ProjectInfoStatus status where lower(status.idProjectInfoStatus) = :statusId
这是与HQL FROM子句相关的link to Hibernate documentation。
另请尝试遵循标准Java命名约定。它将使您的代码更具可读性：）