Question

我想检查这个SQL是否正确。

"SELECT TOP 1 * FROM (SELECT DISTINCT [Entry Date] FROM [" + group + "]) WHERE [Entry Date]>#" + initDate + "# ORDER BY [Entry Date]"

提前谢谢

解决了：我发现sql完美无缺。我只是在程序中犯了一个小错误。现在解决了。

Answer 1

你想要这个吗？

select min([Entry Date])
from [group]
where [Entry Date] > #" + initDate

或者这个：

select top 1 *
from [group]
where [Entry Date] > #" + initDate
order by [Entry Date]

Answer 2

这应该有用。

SELECT B.* FROM (
SELECT [EntryDate] FROM Group

EXCEPT

SELECT [EntryDate] FROM (

SELECT [EntryDate]
,ROW_NUMBER() OVER (ORDER BY [EntryDate]) AS Rown 
from Group 
                        )A WHERE Rown > 1 )B JOIN Group C ON a.[EntryDate] = B.[EntryDate]

WHERE [Entry Date] > #" + initDate
ORDER BY [Entry Date]

SQL从表中获取第一个不同的值

2 个答案: