Question

这是我的代码：

$text = $_REQUEST["enable"];
$description = 'Debited For Service';

foreach($text as $data)
{
    foreach($check as $data1)
    {
        $insert="INSERT INTO `wallet_transaction`(`wallet_id`, `debit_amount`, `description`) VALUES ('$esc_id', '$data1', '$data', '$description')";
        mysql_query($insert);
    }   
}

结果是运行了这些查询，但我只想要前两个查询：

INSERT INTO `wallet_transaction`(`wallet_id`, `debit_amount`, `description`) VALUES ('2', '200', 'Debited For Service')
INSERT INTO `wallet_transaction`(`wallet_id`, `debit_amount`, `description`) VALUES ('3', '100', 'Debited For Service')

INSERT INTO `wallet_transaction`(`wallet_id`, `debit_amount`, `description`) VALUES ('2', '200', 'Debited For Service')
INSERT INTO `wallet_transaction`(`wallet_id`, `debit_amount`, `description`) VALUES ('3', '100', 'Debited For Service')

Answer 1

只使用一个循环，而不是嵌套循环，并一起访问两个数组的相应元素。

foreach ($text as $i => $data) {
    $data = mysql_real_escape_string($data);
    $data1 = mysql_real_escape_string($check[$i]);
    $insert="INSERT INTO `wallet_transaction`(`wallet_id`, `debit_amount`, `description`) VALUES ('$esc_id', '$data1', '$data', '$description')";
    mysql_query($insert);
}

还有一个问题：您只列出要插入的3列，但您有4个值。我猜这只是一个复制错误。

Answer 2

它可能是因为你在内循环中触发查询，

请一起来，

$text = $_REQUEST["enable"];
$description = 'Debited For Service';
foreach($text as $data)
{
    foreach($check as $data1)
    {
        $inData = $data;    
    }   
    $insert="INSERT INTO `wallet_transaction`(`wallet_id`, `debit_amount`, `description`) VALUES ('$esc_id', '$data1', '$inData', '$description')";
    mysql_query($insert);
}

猜这会起作用

Answer 3

替换为以下代码，以便快速解决问题

$quick_fix=1;
foreach($text as $data)
{
    if($quick_fix==1){
        foreach($check as $data1)
        {
            $insert="INSERT INTO `wallet_transaction`(`wallet_id`, `debit_amount`, `description`) VALUES ('$esc_id', '$data1', '$data', '$description')";
            mysql_query($insert);           
        }
        $quick_fix++;
    }
}

将相同的值两次插入数据库

3 个答案: