所以我正在制作一个简单的项目来测试Spring tutorial,并遇到一个我无法弄清楚的问题。
我的项目结构:
的web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.html</url-pattern>
<url-pattern>*.htm</url-pattern>
<url-pattern>*.json</url-pattern>
</servlet-mapping>
</web-app>
调度-servlet.xml中:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<context:component-scan base-package="com.itaSS.controller" />
</beans>
HomeController.java:
package com.itaSS.controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
@Controller
public class HomeController {
@RequestMapping("/home")
public String home() {
return "/WEB-INF/jsp/home.jsp";
}
}
所以当在tomcat上部署战争并尝试去localhost:8080 / home.html之后 我明白了:
我确信在web.xml中有些错误或者我错过了什么。 如果有人帮我这个,我将非常感激!
答案 0 :(得分:0)
我认为你的dispatcher-servlet.xml文件中缺少以下行。
<mvc:annotation-driven/>
答案 1 :(得分:0)
您需要在应用程序上下文文件dispatcher-servlet.xml
中定义ViewResolver,如下所示:
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
<property name="prefix" value="/WEB-INF/jsp/"/>
<property name="suffix" value=".jsp"/>
</bean>