Question

我有这个代码用于上传图像和存储在数据库中我想首先将其重命名为随机名称，然后上传并存储在数据库中我应该如何更改我的代码？请帮我！这是我的PHP代码：

$imageFile=$_FILES['image'];
$file_name = $imageFile['name'];

$target_path = "images/news/".$file_name;

if(move_uploaded_file($imageFile['tmp_name'], $target_path)) {
echo "<div id=\"news\">";
 echo "Image : "."<br>".$file_name;
 echo "<br>"; 
 echo "Successfuly Uploaded!";
echo "<br>"; 


    $newstitle = $_POST['title'];
    $newscontent = $_POST['content'];
    $newsimage = "images/news/".$file_name;


    $sql="insert into news (news_title,news_content,news_image,news_date) values ('$newstitle', '$newscontent','$newsimage',' $newsdate')"; 

    if ($conn->query($sql) === TRUE)
    {
        echo "Image Stored in DB!</div>";
    } 
    else 
    {
        echo "Error: " . $sql . "<br>" . $conn->error;
    }

}

Answer 1

试试这个
使用$random = md5(uniqid("") . time());

创建的随机文件名

以下是重命名文件的工作代码

$imageFile = $_FILES['image'];
$file_name = $imageFile['name'];
$random = md5(uniqid("") . time());
$target_path = "images/news/" . $random.$file_name;

if (move_uploaded_file($imageFile['tmp_name'], $target_path)) {
    echo "<div id=\"news\">";
    echo "Image : " . "<br>". $random . $file_name;
    echo "<br>";
    echo "Successfuly Uploaded!";
    echo "<br>";


    $newstitle = $_POST['title'];
    $newscontent = $_POST['content'];
    $newsimage = "images/news/" . $random. $file_name;


    $sql = "insert into news (news_title,news_content,news_image,news_date) values ('$newstitle', '$newscontent','$newsimage',' $newsdate')";

    if ($conn->query($sql) === TRUE) {
        echo "Image Stored in DB!</div>";
    } else {
        echo "Error: " . $sql . "<br>" . $conn->error;
    }
}

随时准备帮助你

在上传过程中重命名图像（PHP）

1 个答案: