echo从数据库中创建的最后一个表名。在这里，我无法回应这个名字

Question

我收到警告 - ＆gt; mysql_fetch_array（）期望参数1为resource，boolean

enter code here
$db // database name
$sql1="SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_TYPE = 'BASE TABLE' AND       TABLE_SCHEMA=".$db." order by create_time desc limit 1";
$res1 = mysql_query($sql1);
if($row = mysql_fetch_array($res1))
echo $row['TABLE_NAME'];
else echo "unable to fetch table name";

Answer 1

您需要在$db变量的包含周围加上引号。改变这一行：

$sql1="SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_TYPE = 'BASE TABLE' AND       TABLE_SCHEMA=".$db." order by create_time desc limit 1";

要：

$sql1="SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_TYPE = 'BASE TABLE' AND       TABLE_SCHEMA='".$db."' order by create_time desc limit 1";

请注意mysql_* functions are deprecated。使用PDO或mysqli_*与prepared statements一起使用可以避免申请中出现security risks。