Question

我想用编号项创建一个动态ListView。在这里，我将SQLite数据库中的值检索到ListView中，实际上它根据存储在数据库中的id进行编号。但我正在使用动态列表视图，所以我想在每次加载ListView时显示从1开始的编号项。例如，预订不同日期和航班机构的机票的人将显示当前日期的最终ListView，包括在该日期预订的人员。

 consider today is 10-12-2014
 person A booked ticket for the date 12-12-2014, so his "id" might be "1" in database.
 person B booked ticket for the date 13-12-2014,so his "id" might be "2" in database.
 person c booked ticket for the date 13-12-2014,so his "id" might be "3" in database.


    but when the day "13-12-2014" comes person B's id should be "1"(no need to have any connection with database, just enough a numberd representation to   show today's list is this. 

like 
 1.person B
 2.person C

  thats all.

这是我的displayadapter类：

 public class DisplayAdapter extends BaseAdapter {

private Context mContext;
private ArrayList<String> id;
private ArrayList<String>name;
private ArrayList<String>phone;


public DisplayAdapter(Context c, ArrayList<String> id,ArrayList<String> name, ArrayList<String> phone) {
    this.mContext = c;

    this.id = id;
    this.name = name;
    this.phone = phone;
}

public int getCount() {
    // TODO Auto-generated method stub

    return id.size();
}

public Object getItem(int position) {
    // TODO Auto-generated method stub


    return null;
}

public long getItemId(int position) {

    // TODO Auto-generated method stub
    return 0;
}

public View getView(int pos, View child, ViewGroup parent) {
    Holder mHolder;
    LayoutInflater layoutInflater;
    if (child == null) {
        layoutInflater = (LayoutInflater) mContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        child = layoutInflater.inflate(R.layout.viewthem, null);
        mHolder = new Holder();
        mHolder.txt_id = (TextView) child.findViewById(R.id.d);
        mHolder.txt_name = (TextView) child.findViewById(R.id.nm);
        mHolder.txt_phone = (TextView) child.findViewById(R.id.ph);
        child.setTag(mHolder);
    } else {
        mHolder = (Holder) child.getTag();
    }
    mHolder.txt_id.setText(id.get(pos));
    mHolder.txt_name.setText(name.get(pos));
    mHolder.txt_phone.setText(phone.get(pos));

    return child;
}

public class Holder {
    TextView txt_id;
    TextView txt_name;
    TextView txt_phone;
}


}

这是我的dbhelper类：

    mydb = new DBhelper(this);

        SQLiteDatabase database = mydb.getWritableDatabase();
        Cursor mCursor=database.rawQuery("SELECT * FROM contacts WHERE dt='"+d+"'", null);

        userId.clear();
        user_name.clear();
        user_phone.clear();
        if (mCursor.moveToFirst()) {
            do {
                userId.add(mCursor.getString(mCursor.getColumnIndex(DBhelper.CONTACTS_COLUMN_ID)));
                user_name.add(mCursor.getString(mCursor.getColumnIndex(DBhelper.CONTACTS_COLUMN_NAME)));
                user_phone.add(mCursor.getString(mCursor.getColumnIndex(DBhelper.CONTACTS_COLUMN_PHONE)));

            } while (mCursor.moveToNext());
        }
        DisplayAdapter disadpt = new DisplayAdapter(token.this,userId, user_name, user_phone);

        obj.setAdapter(disadpt);
        disadpt.notifyDataSetChanged();

        mCursor.close();

Answer 1

如果您希望列表只是编号（如您所说，不考虑数据库中的实际ID），您只需使用pos中收到的getView()参数。并且您可能想要使用pos + 1，因此列表将基于1（更加用户友好）。

假设mHolder.txtId是您要用来显示数字的TextView，正如我在评论中所说，这应该有效：

mHolder.txt_id.setText(String.valueOf(pos + 1));

如果您在尝试时遇到错误，请准确说明错误。

Android使用编号项目制作列表视图

1 个答案: