Question

目前，我使用TreeMap来存储一些x和y坐标，但与ArrayList或HashMap相比，迭代速度非常慢。我使用它是因为我需要subMap()方法，所以即使确切的X值（键）不存在，我也可以在确定的范围内得到X值。

LinkedHashMap与HashMap几乎具有相同的速度，我可以按插入顺序迭代键（我需要在TreeMap中按照比较器执行插入顺序或顺序）但是我没有＆＃ 39; t有submap()方法。在TreeMap中，我可以非常快速地生成子图。

是否有任何数据结构或某种方式来存储有序值（通过插入顺序或比较器）比TreeMap更快，即使精确值不在地图中，也允许获取范围内的子图？我的意思是，也许我想要2到25之间的值，但是2不存在，最近的是3，所以它将从3到25返回一个子图。或者某种方式将此功能添加到LinkedHashMap？

Answer 1

听起来你需要一个TreeMap，它的迭代速度并不比LinkedHashMap慢得多，并且可以满足您的需求。由于HashMap是无序的，因此subMap没有意义。

Answer 2

今天我终于得到了问题的答案。经过一些测试HashMap后，LinkedHashMap和TreeMap的速度比ArrayList慢，我只想将它们用于创建subMaps()的能力。所以我创建了一个扩展ArrayList的新类，它给了我一个非常好的表现，在this答案的帮助下，我创建了快速获取子列表而不是索引的方法。这是完整的课程：

/**
 * The purpose of this class is to be a faster replacement to a {@link java.util.TreeMap} with
 *  the ability to get sublist containing a range of x values. ArrayList access time is O(1) while
 *  {@link java.util.TreeMap} is O(log(n)). When large data is handled the impact on performance is
 *  noticeable.
 */
public class XYDataset extends ArrayList<PointValue> {

    private final float COMPARISON_THRESHOLD = 0.01f;

    final Comparator<PointValue> comparator = new Comparator<PointValue>() {
        @Override
        public int compare(PointValue lhs, PointValue rhs) {
            if (Math.abs(lhs.getX() - rhs.getX()) < COMPARISON_THRESHOLD) return 0;
            return lhs.getX() < rhs.getX() ? -1 : 1;
        }
    };

    public XYDataset(int capacity) {
        super(capacity);
    }

    public XYDataset() {
    }

    public XYDataset(Collection<? extends PointValue> collection) {
        super(collection);
    }

    @Override
    public List<PointValue> subList(int start, int end) {
        return super.subList(start, end);
    }

    /**
     * Generate a sublist containing the range of x values passed
     * @param x1 lower x value
     * @param x2 upper x value
     * @return sublist containing x values from x1 to x2
     */
    public List<PointValue> subList(float x1, float x2){
        /**
         * Collections.binarySearch() returns the index of the search key, if it is contained in the list;
         *  otherwise it returns (-(insertion point) - 1).
         * The insertion point is defined as the point at which the key would be inserted into the list:
         *  the index of the first element greater than the key, or list.size() if all elements in the list
         *  are less than the specified key. Note that this guarantees that the return value will be >= 0 if
         *  and only if the key is found.
         */
        int n1 = Collections.binarySearch(this, new PointValue(x1, 0), comparator);
        int n2 = Collections.binarySearch(this, new PointValue(x2, 0), comparator);

        /**
         * Example, we assume the list is sorted. Based on (https://stackoverflow.com/questions/19198586/search-sorted-listlong-for-closest-and-less-than)
         *
         * long X = 500;
         * List<Long> foo = new Arraylist<>();
         * foo.add(450L);
         * foo.add(451L);
         * foo.add(499L);
         * foo.add(501L);
         * foo.add(550L);
         *
         * If we search for something that isn't in the list you can work backward from the return value
         *  to the index you want. If you search for 500 in your example list, the algorithm would return (-3 - 1) = -4.
         * Thus, you can add 1 to get back to the insertion point (-3), and then multiply by -1 and subtract 1 to get
         *  the index BEFORE the first element GREATER than the one you searched for, which will either be an index that
         *  meets your 2 criteria OR -1 if all elements in the list are greater than the one you searched for.
         */
        if(n1 < 0) n1 = -n1-1;
        if(n2 < 0) n2 = -n2-1;

        return this.subList(n1, n2);
    }
}

PointValue只是一个包含x和y坐标的类。所以现在我只需要调用subList()传递我想要的x坐标范围。在我的情况下，插入顺序也是排序的，这对于使用Collections.binarySearch()

很重要

如何使用LinkedHashMap获取子图？

2 个答案: