Question

我有这种字符串。

'"asdfasdf","123456", this is a message. OK'

我想要做的是根据第一个，第二个引号和消息的其余部分声明变量，直到OK ... （注意：''内部字符串的长度不一致）

$First = "asdfasdf"
$Second = "123456"
$Message = "this is a message"

这甚至可能吗？有类似" "$First","$Second", "$Message" OK "的方式吗？ TIA。

Answer 1

这是CSV文件吗？似乎没有，但如果是，你应该查看php的csv函数，特别是str_getcsv。

如果没有，你应该只是做一个爆炸，或者，或者你认为最准确的任何组合，然后遍历每个数组项。

$string = '"asdfasdf","123456","this is a message. OK"';
$temp = explode('","',$string);
$array = array();
foreach($temp as $key=>$value){
//do stuff with $value and $key
}

Answer 2

您可以使用正则表达式，如下所示：

<强>代码

$raw = '"asdfasdf","123456", this is a message. OK'; // this is your raw text
preg_match('/^"(?P<first>[^"]+)","(?P<second>[^"]+)",\s+(?P<message>.+?) OK/', $raw, $matches); // this looks for the pattern you defined and stores the matches in $matches
print_r($matches); // this just dumps out the array of matching substrings

<强>输出

Array
(
    [0] => "asdfasdf","123456", this is a message. OK
    [first] => asdfasdf
    [1] => asdfasdf
    [second] => 123456
    [2] => 123456
    [message] => this is a message.
    [3] => this is a message.
)

您可以访问各个子字符串，例如$matches['first']，$matches['second']或$matches['message']。

PHP Demo

Regex Demo

在字符串中声明变量

2 个答案: