Question

这就是我试过的......

这只交换第一个链接...我怎么解决这个问题来整理整个链表????

linkedlist类

public class LinkedList {


private Link first;

public void LinkList() {

    first = null;

}public Link find(int key) {
    Link current = first;

    while (current.iData != key) {
        if (current.next == null) {
            return null;
        } else {
            current = current.next;

        }
    }
    return current;
}

public void insertFirst(int idata, String sdata) {
    Link nl1 = new Link(idata, sdata);

    nl1.next = first;
    first = nl1;
}

public Link deleteFirst() {

    Link temp = first;
    first = first.next;
    return temp;
}

public void displayList() {
    System.out.println("List : ");
    Link current = first;
    while (current != null) {
        current.displayLink();
        current = current.next;
    }
    System.out.println("");
}

public Link delete(int key) {
    Link current = first;
    Link previous = first;

    while (current.iData != key) {
        if (current.next == null) {
            return null;
        } else {
            previous = current;
            current = current.next;

        }

    }
    if (current == first) {
        first = first.next;
    } else {
        previous.next = current.next;

    }
    return current;
}

public void insertmidl(int key, int idata, String sdata) {

    Link nl = new Link(2, "name2");
    Link current = first;
    Link previous = first;

    while (current.iData != key) {
        if (current.next == null) 
        {
            System.out.println("");
        } else {
            previous = current;
            current = current.next;

        }

    }

    if (current == first) {

        nl.next = current.next;
        current.next = nl;

    }
    previous.next = nl;
    nl.next = current;

}

public void update(int key, int i, String n) {

    Link tobeupdated = find(key);

    tobeupdated.iData = i;
    tobeupdated.sData = n;


}
public void sort(){

            Link current = first;

   if(current.iData > current.next.iData) {

        Link temp = current.next;
        current.next = current.next.next;
        temp.next = current;
        first = temp;

    }
}

链接类

public class Link {
public int iData;
public String sData;
public Link next;

public Link(int id,String sd)
{
iData =id;
sData =sd;
next = null;
}
public void displayLink()
{
System.out.println(iData+""+sData); 
}
}

有谁可以帮助我？ .................................................. ...............................

Answer 1

此示例提供了如何使用Comparator对LinkedList进行排序。 LinkedList包含用户定义的对象。通过使用Collections.sort（）方法，您可以对LinkedList进行排序。您必须传递包含排序逻辑的Comparator对象。该示例根据最高薪水对Empl对象进行排序。

import java.util.Collections;
import java.util.Comparator;
import java.util.LinkedList;

public class MyLinkedListSort {

    public static void main(String a[]){

        LinkedList<Empl> list = new LinkedList<Empl>();
        list.add(new Empl("Ram",3000));
        list.add(new Empl("John",6000));
        list.add(new Empl("Crish",2000));
        list.add(new Empl("Tom",2400));
        Collections.sort(list,new MySalaryComp());
        System.out.println("Sorted list entries: ");
        for(Empl e:list){
            System.out.println(e);
        }
    }
}

class MySalaryComp implements Comparator<Empl>{

    @Override
    public int compare(Empl e1, Empl e2) {
        if(e1.getSalary() < e2.getSalary()){
            return 1;
        } else {
            return -1;
        }
    }
}

class Empl{

    private String name;
    private int salary;

    public Empl(String n, int s){
        this.name = n;
        this.salary = s;
    }

    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public int getSalary() {
        return salary;
    }
    public void setSalary(int salary) {
        this.salary = salary;
    }
    public String toString(){
        return "Name: "+this.name+"-- Salary: "+this.salary;
    }
}

如何按升序对链表进行排序

1 个答案: