OrangeBlock
是一个带有文字的橙色块。它实现为StackPane
,其中包含矩形顶部的文本。 (这种方法在the documentation for StackPane中得到证明。)
我已经在坐标(100,80)处放置了OrangeBlock
,现在正试图让它平稳地移动到某些目标坐标。不幸的是,我在路上遇到了一个令人讨厌的问题:
由于某种原因,PathElement
s中的坐标是相对于橙色块解释的。
这是为什么?如何沿着具有绝对坐标的路径进行OrangeBlock
旅行?下面的最小工作示例。
import javafx.animation.PathTransition;
import javafx.application.Application;
import javafx.scene.*;
import javafx.scene.layout.StackPane;
import javafx.scene.paint.Color;
import javafx.scene.shape.*;
import javafx.scene.text.Text;
import javafx.stage.Stage;
import javafx.util.Duration;
public class PathTransitionExample extends Application {
@Override
public void start(Stage primaryStage) throws Exception {
Group root = new Group();
OrangeBlock block = new OrangeBlock(60, 40);
block.relocate(100, 80);
root.getChildren().add(block);
PathTransition transition = newPathTransitionTo(block, 460, 320);
primaryStage.setScene(new Scene(root, 600, 400));
primaryStage.show();
transition.play();
}
private static PathTransition newPathTransitionTo(OrangeBlock block,
double toX, double toY) {
double fromX = block.getLayoutX();
double fromY = block.getLayoutY();
Path path = new Path();
path.getElements().add(new MoveTo(fromX, fromY));
path.getElements().add(new LineTo(toX, toY));
PathTransition transition = new PathTransition();
transition.setPath(path);
transition.setNode(block);
transition.setDelay(Duration.seconds(1));
transition.setDuration(Duration.seconds(2));
return transition;
}
public static void main(String[] args) {
launch(args);
}
private static class OrangeBlock extends StackPane {
public OrangeBlock(int width, int height) {
Rectangle rectangle = new Rectangle(width, height, Color.ORANGE);
Text text = new Text("Block");
getChildren().addAll(rectangle, text);
}
}
}
答案 0 :(得分:7)
出于好奇,我调试了JavaFX代码。似乎你运气不好找到合适的解决方案。这里发生了什么:
PathTransition代码有一个方法interpolate(double frac),其中包括:
cachedNode.setTranslateX(x - cachedNode.impl_getPivotX());
cachedNode.setTranslateY(y - cachedNode.impl_getPivotY());
impl_getPivotX()和impl_getPivotY()方法包含:
public final double impl_getPivotX() {
final Bounds bounds = getLayoutBounds();
return bounds.getMinX() + bounds.getWidth()/2;
}
public final double impl_getPivotY() {
final Bounds bounds = getLayoutBounds();
return bounds.getMinY() + bounds.getHeight()/2;
}
因此PathTransition始终使用节点的中心进行计算。换句话说,这适用于e。 G。一个Circle节点,但没有e。 G。一个Rectangle节点。此外,您需要layoutBounds,因此必须在边界可用后创建PathTransition。
您可以在PathTransition代码中看到计算都是相对的,并且已经涉及布局位置。所以在你的行中你必须考虑这一点。
值得注意的是LineTo类有一个方法setAbsolut(boolean)。但是它并没有解决你的问题。
所以我的问题解决方案是
这对我有用(我添加了一个Rectangle形状来直观地识别正确的边界):
public class PathTransitionExampleWorking2 extends Application {
@Override
public void start(Stage primaryStage) throws Exception {
Group root = new Group();
Rectangle rect = new Rectangle( 100, 80, 460-100+60, 320-80+40);
root.getChildren().add(rect);
OrangeBlock block = new OrangeBlock(60, 40);
block.relocate( 100, 80);
root.getChildren().add(block);
primaryStage.setScene(new Scene(root, 600, 400));
primaryStage.show();
// layout bounds are used in path transition => PathTransition creation must happen when they are available
PathTransition transition = newPathTransitionTo(block, 460, 320);
transition.play();
}
private static PathTransition newPathTransitionTo(OrangeBlock block, double toX, double toY) {
double fromX = block.getLayoutBounds().getWidth() / 2;
double fromY = block.getLayoutBounds().getHeight() / 2;
toX -= block.getLayoutX() - block.getLayoutBounds().getWidth() / 2;
toY -= block.getLayoutY() - block.getLayoutBounds().getHeight() / 2;
Path path = new Path();
path.getElements().add(new MoveTo(fromX, fromY));
path.getElements().add(new LineTo(toX, toY));
PathTransition transition = new PathTransition();
transition.setPath(path);
transition.setNode(block);
transition.setDelay(Duration.seconds(1));
transition.setDuration(Duration.seconds(2));
return transition;
}
public static void main(String[] args) {
launch(args);
}
private static class OrangeBlock extends StackPane {
public OrangeBlock(int width, int height) {
Rectangle rectangle = new Rectangle(width, height, Color.ORANGE);
Text text = new Text("Block");
getChildren().addAll(rectangle, text);
}
}
}
编辑:另一个解决方案是使用它而不是MoveTo和LineTo:
public static class MoveToAbs extends MoveTo {
public MoveToAbs( Node node) {
super( node.getLayoutBounds().getWidth() / 2, node.getLayoutBounds().getHeight() / 2);
}
}
public static class LineToAbs extends LineTo {
public LineToAbs( Node node, double x, double y) {
super( x - node.getLayoutX() + node.getLayoutBounds().getWidth() / 2, y - node.getLayoutY() + node.getLayoutBounds().getHeight() / 2);
}
}
注意:在创建primaryStage之后,您仍然需要创建PathTransition。
编辑:这是另一个示例,其中块移动到鼠标单击的位置:
public class PathTransitionExample extends Application {
@Override
public void start(Stage primaryStage) throws Exception {
Group root = new Group();
OrangeBlock block = new OrangeBlock(60, 40);
block.relocate(100, 80);
root.getChildren().add(block);
Label label = new Label( "Click on scene to set destination");
label.relocate(0, 0);
root.getChildren().add(label);
Scene scene = new Scene(root, 600, 400);
scene.addEventFilter(MouseEvent.MOUSE_CLICKED, new EventHandler<Event>() {
PathTransition transition;
{
transition = new PathTransition();
transition.setNode(block);
transition.setDuration(Duration.seconds(2));
}
@Override
public void handle(Event event) {
transition.stop();
setPositionFixed(block.getLayoutX() + block.getTranslateX(), block.getLayoutY() + block.getTranslateY());
double x = ((MouseEvent) event).getX();
double y = ((MouseEvent) event).getY();
Path path = new Path();
path.getElements().add(new MoveToAbs( block));
path.getElements().add(new LineToAbs( block, x, y));
transition.setPath(path);
transition.play();
}
private void setPositionFixed( double x, double y) {
block.relocate(x, y);
block.setTranslateX(0);
block.setTranslateY(0);
}
});
primaryStage.setScene( scene);
primaryStage.show();
PathTransition transition = newPathTransitionTo(block, 460, 320);
transition.play();
}
private static PathTransition newPathTransitionTo(OrangeBlock block, double toX, double toY) {
Path path = new Path();
path.getElements().add(new MoveToAbs( block));
path.getElements().add(new LineToAbs( block, toX, toY));
PathTransition transition = new PathTransition();
transition.setPath(path);
transition.setNode(block);
transition.setDelay(Duration.seconds(1));
transition.setDuration(Duration.seconds(2));
return transition;
}
public static void main(String[] args) {
launch(args);
}
private static class OrangeBlock extends StackPane {
public OrangeBlock(int width, int height) {
Rectangle rectangle = new Rectangle(width, height, Color.ORANGE);
Text text = new Text("Block");
getChildren().addAll(rectangle, text);
}
}
public static class MoveToAbs extends MoveTo {
public MoveToAbs( Node node) {
super( node.getLayoutBounds().getWidth() / 2, node.getLayoutBounds().getHeight() / 2);
}
}
public static class LineToAbs extends LineTo {
public LineToAbs( Node node, double x, double y) {
super( x - node.getLayoutX() + node.getLayoutBounds().getWidth() / 2, y - node.getLayoutY() + node.getLayoutBounds().getHeight() / 2);
}
}
}
答案 1 :(得分:3)
我现在使用的解决方案是在相反的方向上简单地偏移layoutX
的{{1}}和layoutY
。
Path
在private static void offsetPathForAbsoluteCoords(Path path, OrangeBlock block) {
Node rectangle = block.getChildren().iterator().next();
double width = rectangle.getLayoutBounds().getWidth();
double height = rectangle.getLayoutBounds().getHeight();
path.setLayoutX(-block.getLayoutX() + width / 2);
path.setLayoutY(-block.getLayoutY() + height / 2);
}
实例化后立即插入对此方法的调用可以解决问题。
我对此解决方案并不满意。我不明白为什么Path
和layoutX
需要参与其中。有更简洁的方式吗?
答案 2 :(得分:3)
基本上,
relocate(x,y)方法设置布局 x / y值... Transition使用translateX / Y值...
我可能错了,但我相信当任一值无效时,场景会在场景中的节点上运行“布局”传递。
当发生这种情况时,它会尝试将节点设置为已知的layoutX / Y值,这些值在调用relocate(x,y)时设置(布局值默认为0,0)。
这导致节点在每个步骤的转换中以“layoutPosition”和“pathPosition”绘制,导致抖动和节点偏离应有的位置。
@Override
public void start(Stage primaryStage) throws Exception {
Group root = new Group();
OrangeBlock block = new OrangeBlock(60, 40);
System.out.println(block.getLayoutX() + " : " + block.getLayoutY());
block.relocate(100, 80);
//block.setTranslateX(100);
//block.setTranslateY(80);
System.out.println(block.getLayoutX() + " : " + block.getLayoutY());
root.getChildren().add(block);
PathTransition transition = newPathTransitionTo(block, 460, 320);
transition.currentTimeProperty().addListener(e->{
System.out.println("\nLayout Values: " + block.getLayoutX() + " : " + block.getLayoutY()
+"\nTranslate Values:" + block.getTranslateX() + " : " + block.getTranslateY()
);});
primaryStage.setScene(new Scene(root, 600, 400));
primaryStage.show();
transition.play();
}
private static PathTransition newPathTransitionTo(OrangeBlock block,
double toX, double toY) {
double fromX = block.getLayoutX();//getTranslateX();
double fromY = block.getLayoutY();//getTranslateY();
Path path = new Path();
path.getElements().add(new MoveTo(fromX, fromY));
path.getElements().add(new LineTo(toX, toY));
PathTransition transition = new PathTransition();
transition.setPath(path);
transition.setNode(block);
transition.setDelay(Duration.seconds(1));
transition.setDuration(Duration.seconds(2));
return transition;
}
public static void main(String[] args) {
launch(args);
}
private static class OrangeBlock extends StackPane {
public OrangeBlock(int width, int height) {
Rectangle rectangle = new Rectangle(width, height, Color.ORANGE);
Text text = new Text("Block");
getChildren().addAll(rectangle, text);
}
}
不打算发布图片,但我的第一个结果就像你的第一篇文章,将其更改为上面的代码给了我第二篇文章结果。
由于这些原因,通常最好避免动态(移动)对象上的“布局”值。如果您喜欢重定位方法的便利性,我会实现您自己设置的转换值。
干杯:)
修改强> 我编辑了一些代码来打印转换正在运行时会发生什么,这样你就可以看到原始版本中会发生什么......
答案 3 :(得分:2)
@ jdub1581和@Lorand都给出了有效点:
translateXProperty()
和translateYProperty()
。我还要再添加一件事:
让我们向该群组添加pathScene
:
Path pathScene = new Path();
pathScene.getElements().add(new MoveTo( block.getLayoutX(), block.getLayoutY()));
pathScene.getElements().add(new LineTo(460, 320));
root.getChildren().add(pathScene);
这将是我们现在的场景(为了清晰起见,我添加了两个带有原点和路径末端坐标的标签):
现在我们需要确定本地路径,因此我们将pathScene
元素更改为块的本地坐标,并将其转换为其中心:
Path pathLocal = new Path();
pathScene.getElements().forEach(elem->{
if(elem instanceof MoveTo){
Point2D m = block.sceneToLocal(((MoveTo)elem).getX(),((MoveTo)elem).getY());
Point2D mc = new Point2D(m.getX()+block.getWidth()/2d,m.getY()+block.getHeight()/2d);
pathLocal.getElements().add(new MoveTo(mc.getX(),mc.getY()));
} else if(elem instanceof LineTo){
Point2D l = block.sceneToLocal(((LineTo)elem).getX(),((LineTo)elem).getY());
Point2D lc = new Point2D(l.getX()+block.getWidth()/2d,l.getY()+block.getHeight()/2d);
pathLocal.getElements().add(new LineTo(lc.getX(),lc.getY()));
}
});
正如@Lorand所提到的,这应该在显示阶段后计算块的大小。
现在我们可以创建过渡并播放它。
PathTransition transition = new PathTransition();
transition.setPath(pathLocal);
transition.setNode(block);
transition.setDelay(Duration.seconds(1));
transition.setDuration(Duration.seconds(2));
transition.play();
最后,这是我们需要使块完全遵循所需路径的所有代码:
@Override
public void start(Stage primaryStage) throws Exception {
Group root = new Group();
OrangeBlock block = new OrangeBlock(60, 40);
block.relocate(100, 80);
root.getChildren().add(block);
// Path in scene coordinates, added to group
// in order to visualize the transition path for the block to follow
Path pathScene = new Path();
pathScene.getElements().add(new MoveTo(block.getLayoutX(), block.getLayoutY()));
pathScene.getElements().add(new LineTo(460, 320));
root.getChildren().add(pathScene);
primaryStage.setScene(new Scene(root, 600, 400));
primaryStage.show();
PathTransition transition = newPathTransitionTo(pathScene, block);
transition.play();
}
private PathTransition newPathTransitionTo(Path pathScene, OrangeBlock block) {
// Calculate the path in local coordinates of the block
// so transition is applied to the block without bumps
Path pathLocal = new Path();
pathScene.getElements().forEach(elem->{
if(elem instanceof MoveTo){
Point2D m = block.sceneToLocal(((MoveTo)elem).getX(),((MoveTo)elem).getY());
Point2D mc = new Point2D(m.getX()+block.getWidth()/2d,m.getY()+block.getHeight()/2d);
pathLocal.getElements().add(new MoveTo(mc.getX(),mc.getY()));
} else if(elem instanceof LineTo){
Point2D l = block.sceneToLocal(((LineTo)elem).getX(),((LineTo)elem).getY());
Point2D lc = new Point2D(l.getX()+block.getWidth()/2d,l.getY()+block.getHeight()/2d);
pathLocal.getElements().add(new LineTo(lc.getX(),lc.getY()));
}
});
PathTransition transition = new PathTransition();
transition.setPath(pathLocal);
transition.setNode(block);
transition.setDelay(Duration.seconds(1));
transition.setDuration(Duration.seconds(2));
return transition;
}
public static void main(String[] args) {
launch(args);
}
private static class OrangeBlock extends StackPane {
public OrangeBlock(int width, int height) {
Rectangle rectangle = new Rectangle(width, height, Color.ORANGE);
Text text = new Text("Block");
getChildren().addAll(rectangle, text);
}
}
请注意,此解决方案等同于@Lorand提供的解决方案。
如果我们监视块的X,Y转换属性,它们从(0,0)到(360,240),它们只是全局路径上的相对属性。
答案 4 :(得分:1)
您正在使用重定位功能来定位您的Block。重定位函数在x和y上进行计算以定位对象。如果您使用setLayoutX找到Block然后使用getLayoutX,则可能不会发生此问题。相同的解释对y属性有效。
您可以在此处找到有关您的问题的一些信息:http://docs.oracle.com/javase/8/javafx/api/javafx/scene/Node.html#layoutXProperty