Question

我以前从未处理过这样的请求，而且我不知道在互联网上搜索什么... 所以我有这个任务，我有一个api url - https://www.myurl.com/oauth2/2.0/signin 它应该提供一个电子邮件和密码。网址接受post方法（我有点不知道这意味着什么），如果成功，应提供JSON对象，但我不知道如何在链接中提供电子邮件和密码。。我有这个AsyncTask

public class JSONGet extends AsyncTask<String, Void, String> {

String adres;
JSONObject jsonGet;
JSONParserCallback delegate;

public JSONGet(JSONParserCallback callback, String adres) {
    this.delegate = callback;
    this.adres = adres;
}

@Override
protected String doInBackground(String... params) {
    try {
        HttpClient client = new DefaultHttpClient();
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs.add(new BasicNameValuePair("testemail@mail.uk", "android"));
        HttpPost httppost = new HttpPost("https://www.myurl.com/oauth2/2.0/signin");
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        HttpResponse hr = client.execute(httppost);
        int status = hr.getStatusLine().getStatusCode();
        if (status == 200) {
            HttpEntity he = hr.getEntity();
            String data = EntityUtils.toString(he);
            jsonGet = new JSONObject(data);
        }
    } catch (IOException e) {
        e.printStackTrace();
    } catch (JSONException e) {
        e.printStackTrace();
    }
    return null;
}

@Override
protected void onPostExecute(String result) {
    super.onPostExecute(result);
    delegate.onFinishedParsing(jsonGet);
}

}

Answer 1

您可以提供如下用户名和密码：

    nameValuePairs.add(new BasicNameValuePair("userName","{username string}"));
    nameValuePairs.add(new BasicNameValuePair("password","{password string}"));

将{username string} and {password string}替换为您的用户名和密码。

Android使用Post方法使用电子邮件和密码解析JSON

1 个答案: