怎么得到表狮身人面像的名字?

时间:2014-12-26 12:33:13

标签: php sphinx

我使用PHP sphinx客户端(PECL):

$s = new SphinxClient; $s->setServer("localhost", 9312);
$s->setMaxQueryTime(9000);
$s->setMatchMode(SPH_MATCH_ANY);

$result = $s->query($_POST['search'], '*');
var_dump($result);

请求后我得到一个输出数组:

 ["fields"]=>
  array(4) {
    [0]=>
    string(4) "type"
    [1]=>
    string(18) "specializationname"
    [2]=>
    string(17) "detailtousersname"
    [3]=>
    string(18) "detailtousersphoto"
  }

在输出数组中,我试图获取表的名称,其中找到了数据(ID' s)。这个设置我在sphinx.conf中设置:

sql_query = SELECT idArticle as id, 'article' as type...
sql_field_string  = type

如何获取表名'article'

来源 config 示例:

source users : lsParentSource
{

    sql_query_range   = SELECT MIN(idDetailToUsers), MAX(idDetailToUsers) FROM detailtousers
    sql_range_step    = 128
    sql_query         = SELECT idDetailToUsers as id, 9 as type, UsersTypeAccount, idDetailToUsers, SpecializationName, DetailToUsersName, DetailToUsersPhoto, city, country FROM detailtousers join users ON users.idUsers = detailtousers.idDetailToUsers left join usersspecialization ON usersspecialization.UsersSpecializationIdUser = detailtousers.idDetailToUsers left join specializationtousers ON specializationtousers.idSpecialization = usersspecialization.UsersSpecializationIdSpecialization WHERE idDetailToUsers >= $start AND idDetailToUsers <= $end GROUP BY idDetailToUsers

    sql_attr_uint     = type
    sql_attr_uint     = idDetailToUsers
    sql_attr_uint     = UsersTypeAccount
    sql_field_string  = SpecializationName
    sql_field_string  = DetailToUsersName
    sql_field_string  = DetailToUsersPhoto
    sql_attr_uint     = city
    sql_attr_uint     = country

    sql_query_info    = SELECT idDetailToUsers, DetailToUsersName, UsersTypeAccount, SpecializationName, DetailToUsersPhoto, city, country \
                        FROM detailtousers WHERE idDetailToUsers = $id
    sql_ranged_throttle = 0
}

1 个答案:

答案 0 :(得分:0)

结果数组应该包含一个&#39; attrs&#39;匹配数组中的数组(每个文档一个)。