Question

我跟随json

{
"id": 81,
"bank_id": 2,
"service_id": 1,
"created_at": "2014-12-05 06:40:23",
"updated_at": "2014-12-05 06:40:23",
"alias": "remit",
"alias_burmese": "remit",
"reputation": null,
"contact": null,
"service": null
},
{
"id": 82,
"bank_id": 2,
"service_id": 2,
"created_at": "2014-12-05 06:40:24",
"updated_at": "2014-12-05 06:40:24",
"alias": "international remit",
"alias_burmese": "international remit",
"reputation": {
"id": 1,
"bank_service_id": 82,
"reputation_points": "-2",
"created_at": "2014-12-25 10:08:40",
"updated_at": "2014-12-25 10:08:40"
},
"contact": null,
"service": {
  "id": 2,
  "parent_id": 1,
  "service": "International Remittance",
  "service_burmese": "International Remittance",
  "is_active": "1",
  "created_at": "2014-09-12 08:31:57",
  "updated_at": "2014-09-12 08:31:57",
  "service_order": 1
}
}

我想忽略条目将为NULL服务..所以我的条目将如下所示

{
    "id": 82,
    "bank_id": 2,
    "service_id": 2,
    "created_at": "2014-12-05 06:40:24",
    "updated_at": "2014-12-05 06:40:24",
    "alias": "international remit",
    "alias_burmese": "international remit",
    "reputation": {
    "id": 1,
    "bank_service_id": 82,
    "reputation_points": "-2",
    "created_at": "2014-12-25 10:08:40",
    "updated_at": "2014-12-25 10:08:40"
    },
    "contact": null,
    "service": {
      "id": 2,
      "parent_id": 1,
      "service": "International Remittance",
      "service_burmese": "International Remittance",
      "is_active": "1",
      "created_at": "2014-09-12 08:31:57",
      "updated_at": "2014-09-12 08:31:57",
      "service_order": 1
    }
    }

什么是最好的选择..我试图将json转换为数组并尝试使用array_filter进行过滤？

Answer 1

是的，您可以使用array_filter，json_decode和json_encode来实现这一目标。请注意，在用数组表示法[]包装它之前，您的JSON示例无效。

<?php
// callback function for array_filter
function filterNullService($obj) {
  if(!is_null($obj->service)){
    return $obj;
  }
}

$json = '[{
  "id": 81,
  "bank_id": 2,
  "service_id": 1,
  "created_at": "2014-12-05 06:40:23",
  "updated_at": "2014-12-05 06:40:23",
  "alias": "remit",
  "alias_burmese": "remit",
  "reputation": null,
  "contact": null,
  "service": null
},
{
  "id": 82,
  "bank_id": 2,
  "service_id": 2,
  "created_at": "2014-12-05 06:40:24",
  "updated_at": "2014-12-05 06:40:24",
  "alias": "international remit",
  "alias_burmese": "international remit",
  "reputation": {
    "id": 1,
    "bank_service_id": 82,
    "reputation_points": "-2",
    "created_at": "2014-12-25 10:08:40",
    "updated_at": "2014-12-25 10:08:40"
  },
  "contact": null,
  "service": {
    "id": 2,
    "parent_id": 1,
    "service": "International Remittance",
    "service_burmese": "International Remittance",
    "is_active": "1",
    "created_at": "2014-09-12 08:31:57",
    "updated_at": "2014-09-12 08:31:57",
    "service_order": 1
  }
}]';
$array = json_decode($json);

$result = array_filter($array, "filterNullService");
$jsonResult = json_encode($result);

echo "<pre>";
print_r($result);
print_r($jsonResult);
echo "</pre>";

Answer 2

是的，您需要使用json_decode函数将第二个参数作为true将JSON字符串转换为数组。然后使用array_filter过滤数组，并使用json_encode

将数组编码为JSON

如果您需要示例代码，请与我们联系。

使用null子级过滤json条目

2 个答案: