如何检查字符串是否包含从a到z的所有字符？

Question

输入为：

wyyga
qwertyuioplkjhgfdsazxcvbnm
ejuxggfsts

输出应为：

NO
YES
NO

Answer 1

^(?=.*a)(?=.*b)(?=.*c)(?=.*d)(?=.*e)(?=.*f)(?=.*g)...and so on.....till (?=.*y)(?=.*z)[a-z]+$

你可以尝试一下。参见演示。

https://regex101.com/r/dL7oF8/3

Answer 2

你试试这个

 ^(?=.*a)(?=.*b)(?=.*c)(?=.*d)(?=.*e)(?=.*f)(?=.*g)(?=.*h)(?=.*i)(?=.*j)(?=.*k)(?=.*l)(?=.*m)(?=.*n)(?=.*o)(?=.*p)(?=.*q)(?=.*r)(?=.*s)(?=.*t)(?=.*u)(?=.*v)(?=.*w)(?=.*x)(?=.*y)(?=.*z)[a-z]+$

• 它将作为正则表达式
• 如果有任何问题的答案请评论我