Question

我有这个案子：

list = ["Translate:(0,0,0)", "Scale:(1,1,1)", "Rotate:(0,180,0)"]
str = "Rotate:"

我想基于传入的字符串str对此列表进行排序，在这种情况下是“旋转：”，因此包含“旋转：”的项目将转到列表中的第一个位置。我不关心其余元素的顺序。像这样：

["Rotate:(0,180,0)", "Scale:(1,1,1)", "Translate:(0,0,0)"]

是否可以通过key = lambda ...使用“已排序”功能等等或cmp来实现？或者我必须做更复杂的循环和比较来重建列表？

Answer 1

使用str_ in x作为密钥：

>>> list_ = ["Translate:(0,0,0)","Scale:(1,1,1)", "Rotate:(0,180,0)"]
>>> str_ = "Rotate:"
>>> sorted(list_, key=lambda x:str_ in x, reverse=True)
['Rotate:(0,180,0)', 'Translate:(0,0,0)', 'Scale:(1,1,1)']

Answer 2

def bring_to_front(lst, match_str):
    """
    Given a list of strings and a match string,
    return a copy of the list with all items
    beginning with match_str moved to the head of the list
    """
    return sorted(lst, key = lambda s: s.startswith(match_str), reverse=True)

然后

>>> lst = ["Translate:(0,0,0)", "Rotate:(0,0,90)", "Scale:(1,1,1)", "Rotate:(0,180,0)"]
>>> bring_to_front(lst, "Rotate:")
['Rotate:(0,0,90)', 'Rotate:(0,180,0)', 'Translate:(0,0,0)', 'Scale:(1,1,1)']

Answer 3

if "Rot" in word: # "Rotate()" returns True
    liste.remove(word) # remove the word
    liste.insert(0, word) # insert it again as first position

如果包含特定字符，将列表内的字符串排序到第一个位

3 个答案: