Question

我的数据库中有三个表，想要插入一些数据，但我似乎无法使其正常工作。

数据库结构（mysql＆amp; InnoDB）

book

book_id (AI & Primary Key)
book_original_name

writer

writer_id (AI & Primary Key)
writer_name

book_who_wrote_it

book_id (Foreign Key from book table)
writer_id (Foreign Key from writer table)

我想做的是：

1-）在书表中插入一本新书。

2-）将数据插入联结表。（包含book_id和writer_id）

3-）我不想添加新的编写者，并希望将现有的编写者添加到我的联结表中，我的编写者表包含了我想要的所有编写者。

这就是我迄今为止尝试过的事情。（$ sqli是我的连接变量）

$add_book_original_name = htmlspecialchars($_POST['book_original_name']);
$add_book_original_name = mysqli_real_escape_string($sqli, $add_book_original_name);

$stmt = $sqli->prepare("INSERT INTO book(book_original_name) VALUES (?)");
$stmt->bind_param("s", $add_book_original_name);
$stmt->execute();
$stmt->close();

    // junction table stuff

    $get_book_id = $sqli->insert_id; // I am trying to get the last inserted book id
    $get_writer_id = $sqli->prepare("SELECT writer_id FROM writer WHERE writer_name = $add_book_writer_name ");
    $stmt->bind_param("i", $get_writer_id);
    $stmt->execute();
    $stmt->close();

    $stmt = $sqli->prepare("INSERT INTO book_who_wrote_it(book_id, writer_id) VALUES($get_book_id, $get_writer_id)");
    $stmt->bind_param("ii", $get_book_id, $get_writer_id);
    $stmt->execute();
    $stmt->close();

使用SQL插入表和联结表

0 个答案: