Question

由于鼠标按下事件，正在执行以下线程：

// simulates bouncing ball
class Ball extends JPanel implements Runnable {  
  int Horz = 200;  
  int Vert = 200;  
  int xDim = 10;  
  int yDim = 10;  
  private int xPos;  
  private int yPos;  
  private int dxPos;  
  private int dyPos;  

  // constructor - set initial ball position to where mouse clicked; deltas to random numbers
  public Ball(int startx, int starty)  
  {  
    xPos   = startx;  
    yPos   = starty;  
    dxPos =  (int) (Math.random() * 5 + 2);  
    dyPos =  (int) (Math.random() * 5 + 2);  
  }
  // logic to update position of ball
  public void move() {

    xPos += dxPos;
    yPos += dyPos;

    if (xPos < 0) {
      xPos = 0;
      dxPos = -dxPos;
    }
    if (xPos + xDim >= Horz) {
      xPos = Horz - xDim;
      dxPos = -dxPos;
    }
    if (yPos < 0) {
      yPos = 0;
      dyPos = -dyPos;
    }

    if (yPos + yDim >= Vert) {
      yPos = Vert - yDim;
      dyPos = -dyPos;
    }
  }

调用Run方法调用repaint

  @Override
  // run --- paint, sleep, update position - this is being executed
  public void run()     
  {  
    while (true)  
    {         
        System.out.println("I am in RUN");  
        repaint();  

        try
        {
            // sleep thread for 20 milliseconds
            Thread.sleep(20);
        }
        catch (InterruptedException e)
        {
            // interrupted
            System.out.println("Terminated prematurely due to interruption");
        }

        move();               
    }   
  }

但是油漆没有被称为

     // draw ball at current position  
     @Override  
     public void paint( Graphics g )  
     {  
       // THIS IS NOT BEING EXECUTED  
       System.out.println("I am in paint");  

       super.paint( g );  
       g.setColor( Color.BLUE );   
       g.fillOval( xPos, yPos, 10, 10 );   
    }   
}

为什么？是不是应该重新调用paint方法？

Answer 1

重绘不会立即调用油漆;它会调度要重新绘制的组件，这会在事件队列到达时立即调用paint。您很可能通过在其上运行计时器循环来阻止event dispatch thread，因此它无法处理绘制事件（或任何其他事件）。在不同的线程上运行循环，或者（更简单，更安全）用Swing Timer替换它：

Timer t = new Timer(20, (ActionEvent e) -> {
    move();
    repaint();
});
t.start();

Answer 2

@Boan是对的。虽然我先看看线程是否已启动：

Thread((Ball)ball);
thread.setDaemon(true);
thread.start();

调用repaint不会导致在线程中调用paint方法

2 个答案: