我是Android开发的新手,今天刚刚发现了Retrofit。我希望构建一个消耗我网站API的Android应用程序,看起来Retrofit很适合这个账单。
我正在尝试使用我的API中以JSON形式返回的数据填充ListView,但无法弄清楚我需要做什么。我已经在我的代码中直接使用虚拟数据填充了ListView(对不起,很多代码):
public class MainActivity extends ActionBarActivity {
public static final String TAG = "App";
public static ListView mListView;
private List<User> users = new ArrayList<User>();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
mListView = (ListView)findViewById(R.id.usersListView);
populateUserList(); // Add items to the Users array
populateListView(); // Add the Users to the List View
}
// Add items to the User List array
// This is what I want to populate from my API
private void populateUserList() {
users.add(new User("Joe Smith", "jsmith@nowhere.com"));
users.add(new User("Frank Smith", "fsmith@somewhere.net"));
users.add(new User("Mary Jane", "mjane@website.org"));
}
//Add the Users Array to the List View
private void populateListView() {
ArrayAdapter<User> adapter = new UserListAdapter();
mListView.setAdapter(adapter);
}
private class UserListAdapter extends ArrayAdapter<User> {
public UserListAdapter(){
super(MainActivity.this, R.layout.user_item, users);
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
View itemView = convertView;
// Check if Item View is null
if (itemView == null)
{
// Need to create a new view - make sure we have a view to work with.
itemView = getLayoutInflater().inflate(R.layout.user_item, parent, false);
}
// Find the user to work with
User currentUser = users.get(position);
// Fill the view
TextView nameField = (TextView)itemView.findViewById(R.id.list_nameField);
TextView emailField = (TextView)itemView.findViewById(R.id.list_emailView);
nameField.setText(currentUser.getName());
emailField.setText(currentUser.getEmail());
return itemView;
}
}
以下是我的Retrofit API代码:
public interface Api {
@GET("/httplist")
List<User> userList();
}
..和我的Rest客户:
public class RestClient {
private static Api REST_CLIENT;
private static String ROOT = "https://somewhere.org";
static {
setupRestClient();
}
private RestClient() {}
public static Api get() {
return REST_CLIENT;
}
private static void setupRestClient() {
RestAdapter.Builder builder = new RestAdapter.Builder()
.setEndpoint(ROOT)
.setClient(new OkClient(new OkHttpClient()))
.setLogLevel(RestAdapter.LogLevel.FULL);
RestAdapter restAdapter = builder.build();
REST_CLIENT = restAdapter.create(Api.class);
}
}
..用户类..
public class User {
private String name;
private String email;
public User(String name, String email) {
super();
this.name = name;
this.email = email;
}
public String getName() {
return name;
}
public String getEmail() {
return email;
}
}
最后,我试图处理一些简单的JSON:
[
{"name":"John Smith","email":"jsmith@somewhere.net"}
...
]
我觉得我很接近,但我似乎无法将其连接起来。非常感谢帮助!感谢。
更新 先这样做。我不得不将API请求放在Runnable中以避免NetworkOnMainThread异常。这些物品没有被添加。
private void populateUserList() {
users.add(new User("Joe Smith", "jsmith@nowhere.com"));
users.add(new User("Frank Smith", "fsmith@somewhere.net"));
users.add(new User("Mary Jane", "mjane@website.org"));
Thread thread = new Thread(new Runnable() {
@Override
public void run() {
try {
users = RestClient.get().userList();
} catch (Exception e) {
e.printStackTrace();
}
}
});
thread.start();
}
答案 0 :(得分:3)
您可以使用由Retrofit提供的REST方法的异步版本。这使您无需为网络操作创建单独的后台线程,并使代码更清晰。获得用户列表后,请更新适配器。您不需要单独的用户阵列。
private void populateUserList() {
RestClient.get().userList(new Callback<List<User>>() {
public void success(List<User> users, Response response) {
// this is called in main thread so it's ok to update views
mUsersAdapter.clear();
mUsersAdapter.addAll(users);
}
public void failure(RetrofitError error) {
// handle error
}
});
}