Question

我已经在这个工作了大约两天了。我正在尝试为我正在测试的iOS移动应用程序设置PHP后端，并且我已经获得了我正在尝试使用mysqli的基本版本，但我想使用{{1相反。

我正在尝试将我从应用程序发送的用户信息存储到测试服务器（在我的计算机上）。到目前为止，我已经找到PDO和UPDATE与SELECT - 但是当我到达我的应用程序发出PDO请求以存储信息的步骤时POST数据库，会发生什么如下：

a。）在我将参数作为参数数组绑定到mysql函数后，它会一直到$stmt->execute()行，或者我使用execute()来在尝试bindValue之前，在foreach循环中单独绑定它们。如果我的代码进入未找到新用户的部分并尝试输入信息，则会发生以下情况：

execute()

这是echo语句的输出完全按照它出现的顺序 - 我会解释我在做什么（我隐藏了值但是它们看起来都是我想要的......我主要是想知道格式化问题...如果我格式化错误导致我的$this->strforvalsie = substr($this->strforvalsie, 0, -1); $this->stforquee = substr($this->stforquee, 0, -1); $this->querystring = substr($this->querystring, 0, -1); $this->hh = $this->makeathing($this->stforquee, $this->querystring); echo "\n\n".$this->hh."\n\n"; $stmt = $this->db->prepare($this->hh); foreach ($this->arrayfordat as $key => $value) { $stmt->bindValue( (string)$key, (string)$value, PDO::PARAM_STR); } echo "\n\n\n\n\n".json_encode($streetch)."\n\n\n\n\n\n"; //return 2 - /*** I use this line to exit the code early...before the hang - to see what the variables look like. I will print the outputs below to help. ***/ if($stmt->execute($streetch)) { /*** IT SEEMS TO HANG HERE AND NEVER MAKE IT TO THE RETURN STATEMENT WHICH IS FOR THE PURPOSES OF EXITING THE INSTANCE OF THE CLASS TO SEND A RESPONSE ***/ return 3; } else { return 2; }请求被POST打破：

mysql

关于所有这一切最令人讨厌的部分...并且希望对任何可以提供帮助的人最有说服力...所有信息都以完全可接受的方式成功存储在数据库中...这只是程序似乎永远不会想要在/*** THIS LINE IS RESPONSIBLE FOR CREATING MY QUERY: $this->hh = $this->makeathing($this->stforquee, $this->querystring); Output below: ***/ INSERT INTO users(username,email,userfirst,userlast,updatedtime,usergender,fbverified,timezone,fbprofilelink,fblocale,fbid) VALUES(:username,:email,:userfirst,:userlast,:updatedtime,:usergender,:fbverified,:timezone,:fbprofilelink,:fblocale,:fbid) /*** THIS IS WHAT A JSON OBJECT LOOKS LIKE OF THE ARRAY THAT I AM PASSING TO THE execute() FUNCTION - created by the line: echo "\n\n\n\n\n".json_encode($streetch)."\n\n\n\n\n\n"; Ouput below: ***/ {":username":"Eamon White",":email":"eamon.white7@gmail.com",":userfirst":"Eamon",":userlast":"White",":updatedtime":"2014-06-15T17:34:06+0000",":usergender":"male",":fbverified":"NO",":timezone":"-5",":fbprofilelink":"https:\/\/www.facebook.com\/app_scoped_user_id\/891510963470\/",":fblocale":"en_US",":fbid":"891510963470"}之后转移到return语句，这样我就可以得到应答方面的响应。任何帮助将不胜感激。总结一下这个问题 - 不能通过该死的execute()陈述：）。

Answer 1

请在以下属性中添加您的连接： $ db-＆gt; setAttribute（PDO :: ATTR_ERRMODE，PDO :: ERRMODE_EXCEPTION）;

是否会输出一些错误？

Answer 2

是的...我是半新手 - 足够有趣......我在我的代码中使用这些方法进行回复：

function getStatusCodeMessage($status)
{
// these could be stored in a .ini file and loaded
// via parse_ini_file()... however, this will suffice
// for an example
$codes = Array(
    100 => 'Continue',
    101 => 'Switching Protocols',
    200 => 'OK',
    201 => 'Created',
    202 => 'Accepted',
    203 => 'Non-Authoritative Information',
    204 => 'No Content',
    205 => 'Reset Content',
    206 => 'Partial Content',
    300 => 'Multiple Choices',
    301 => 'Moved Permanently',
    302 => 'Found',
    303 => 'See Other',
    304 => 'Not Modified',
    305 => 'Use Proxy',
    306 => '(Unused)',
    307 => 'Temporary Redirect',
    400 => 'Bad Request',
    401 => 'Unauthorized',
    402 => 'Payment Required',
    403 => 'Forbidden',
    404 => 'Not Found',
    405 => 'Method Not Allowed',
    406 => 'Not Acceptable',
    407 => 'Proxy Authentication Required',
    408 => 'Request Timeout',
    409 => 'Conflict',
    410 => 'Gone',
    411 => 'Length Required',
    412 => 'Precondition Failed',
    413 => 'Request Entity Too Large',
    414 => 'Request-URI Too Long',
    415 => 'Unsupported Media Type',
    416 => 'Requested Range Not Satisfiable',
    417 => 'Expectation Failed',
    500 => 'Internal Server Error',
    501 => 'Not Implemented',
    502 => 'Bad Gateway',
    503 => 'Service Unavailable',
    504 => 'Gateway Timeout',
    505 => 'HTTP Version Not Supported'
);

return (isset($codes[$status])) ? $codes[$status] : '';
}


// Helper method to send a HTTP response code/message
function sendResponse($status=null, $body = '', $content_type = 'text/html')
{
    $status_header = 'HTTP/1.1 ' . $status . ' ' . getStatusCodeMessage($status);
    header($status_header);
    header('Content-type: ' . $content_type);
    print $body;
}

我使用100响应只是为了使用不同的东西，所以我可以从我的应用程序中解决服务器端发生的事情 - 100响应代表＆＃34;继续＆＃34 ; - 正如您在数字定义中所见。我认为这实际上非常相关......但直到现在我还不知道它会 - 我只是在我的localhost上测试。好奇为什么重要，但它解决了我的问题。

使用PHP PDO INSERT INTO表 - 挂起在execute（）语句中

2 个答案: