Question

我有一个问题：

SELECT case

when Submission__bTracking = 'Phone' then 'Phone'
when Submission__bTracking = 'Web' then 'Web'
when Submission__bTracking = 'Email' then 'Email
when Submission__bTracking = 'Live__bTech__bSupport' then '@ Live Tech Support
when Submission__bTracking = 'Verbal' then 'Verbal Request'
when Submission__bTracking = 'Fax__b__f__bform' then 'Fax / Form'

End as Sub_Tracking,

COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1))
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP))

GROUP BY Submission__bTracking

产生以下结果：

Sub_Tracking               tickets
Email                        36
Fax / Form                    1
@ Live Tech Support          18
Phone                       441
Web                          41

如何同时生成同一查询中所有故障单的总和？

如下所示：

Sub_Tracking               tickets
Email                        36
Fax / Form                    1
@ Live Tech Support          18
Phone                       441
Web                          41
ALL                         537

感谢您的帮助!!

Answer 1

您可以使用UNION，只需在结果集中再添加一行：

YOUR QUERY

UNION ALL
select 'ALL' as Sub_Tracking,
COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1))
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP))

Answer 2

你可以做到

...previous lines omitted
GROUP BY Submission__bTracking
UNION
SELECT 'ALL' as Sub_Tracking, count(Submission__bTracking) as tickets
FROM dbo.MASTER30
WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1))
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP))

Answer 3

这里有两种选择。一种是将您的初始查询与计算所有票证的另一个查询结合起来，例如

SELECT case

when Submission__bTracking = 'Phone' then 'Phone'
when Submission__bTracking = 'Web' then 'Web'
when Submission__bTracking = 'Email' then 'Email
when Submission__bTracking = 'Live__bTech__bSupport' then '@ Live Tech Support
when Submission__bTracking = 'Verbal' then 'Verbal Request'
when Submission__bTracking = 'Fax__b__f__bform' then 'Fax / Form'

End as Sub_Tracking,

COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1))
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP))

GROUP BY Submission__bTracking

UNION ALL

SELECT "All" AS Sub_Tracking,

COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1))
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP))

另一种选择是使用WITH ROLLUP（例如http://dev.mysql.com/doc/refman/5.6/en/group-by-modifiers.html）

看起来像这样：

SELECT case

when Submission__bTracking = 'Phone' then 'Phone'
when Submission__bTracking = 'Web' then 'Web'
when Submission__bTracking = 'Email' then 'Email
when Submission__bTracking = 'Live__bTech__bSupport' then '@ Live Tech Support
when Submission__bTracking = 'Verbal' then 'Verbal Request'
when Submission__bTracking = 'Fax__b__f__bform' then 'Fax / Form'

End as Sub_Tracking,

COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1))
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP))

GROUP BY Submission__bTracking WITH ROLLUP

后一个选项不会输出＆＃34; ALL＆＃34;但是它要短得多......而且，你不能同时使用ORDER BY和WITH ROLLUP，所以也要提前知道。

在两者之间，我可能会使用第一个选项....这与其他响应的人提供的选项相同，只是我使用UNION ALL而不是UNION。这是一个挑剔的细节，但如果您不需要它们，为什么还要重复检查。有关UNION和UNION ALL的更多信息，请查看：What is the difference between UNION and UNION ALL?）

获取相同查询的查询结果的SUM

3 个答案: