Question

我想编写一个代码，例如将此文本：“aaaaaaabbbb”转换为：“a7b4”。它应该从一个文件读取并写入另一个文件。这是代码的错误部分，我无法使其工作。 Ty求助..

        fread(&fx,sizeof(fx),1, fin);      // read first character
        while(!feof(fin))
        {
            fread(&z, sizeof(z),1, fin);           //read next characters 

            if(z!=fx) { fputs(fx, fout);            
                        fputs(poc, fout);              
                        poc=1;                        // if its different count=1 
                        fx=z;               // and z is new character to compare to
                       }
            else poc++;


            }

            fputs(fx, fout);                
            fputs(poc, fout);

Answer 1

fputs(poc, fout); 
      ^^^

poc是整数类型。 fputs()的第一个参数是字符串类型。你不能混合和匹配这两者。

请改为使用：

fprintf(fout, "%d", poc);

但请记住，当计数大于10时，输出有时可能不明确。例如，输出：

可能代表1 x 2, 3 x 45或1 x 23, 4 x 5（例如）。

Answer 2

这是我的代码（不是最佳解决方案）来解决评论问题....希望它有助于您自己的代码和程序!!

#include <stdio.h> 
#include <string.h> 

int main(int argc, char *argv[])
{
    /* file is a pointer to the file input where to read the line  */
    /* fileto is a pointer to the file output where we will put */
    /* the compressed string */
    FILE* file, *fileto;
    file=fopen("path_to_input_file","r");
    fileto=fopen("path_to_output_file","w");
    /* check if the file is successfully opened */
    if (file!=NULL)
    {
        /* the str will contain the non compressed str ing  */
        char str[100];
        /* read the non compressed string from the file and put it */
        /* inside the variable str via the function fscanf */
        fscanf(file,"%[^\n]s",str);
        /* the variable i will serve for moving character by character */
        /* the variable nb is for counting the repeated char */
        int i=0,nb=1;
        for (i=1;i<strlen(str);i++)
        {
            /* initialization */
            nb=1;
            fprintf(fileto,"%c",str[i-1]);
            /* loop to check the repeated charac ters */
            while (i<strlen(str) && str[i]==str[i-1])
            {
                i++;
                nb++;
            }
            fprintf(fileto,"%d",nb);

        }
        /* handle the exception for the last character  */
        if(strlen(str)>=2 && str[strlen(str)-1]!=str[strlen(str)-2]) 
            fprintf(fileto,"%c%d",str[strlen(str)-1],1);
            /* handle the string when it is composed only by one  char */
        if(strlen(str)==1)
            fprintf(fileto,"%s%d\n",str,nb);



        fclose(fileto);
        fclose(file);
    }

    return 0;
}

RLE文本压缩在c

2 个答案: