Question

我正在制作游戏，我希望玩家能够以“X＆＃39;位于屏幕中间的一半位置，以及一个＆＃39; Y＆＃39;播放器底部位于屏幕底部上方5个像素的位置。我尝试使用显示和显示指标来获取屏幕大小并设置相对于此的x和y位置，但它看起来不起作用。图像根本不在屏幕上绘制。我只是得到一个空白的屏幕。如果我给出恒定坐标（ex.100,50），它可以工作。这就是我现在想要实现的目标：

x = (displayMetrics.widthPixels / 2); y = displayMetrics.heightPixels - (height + 5);

这是自定义视图将其绘制到屏幕的方式：

canvas.drawBitmap(player.getImage(), player.getX(), player.getY(), null);

自定义视图类 -

public class GameGraphics extends SurfaceView implements Runnable {

private SurfaceHolder surfaceHolder;
private Thread gameGraphics;
private GameCore gameCore;
private Player player;

public GameGraphics(Context context, GameCore gameCore) {
    super(context);
    this.gameCore = gameCore;
    this.player = gameCore.getPlayer();
    surfaceHolder = getHolder();
    gameGraphics = new Thread(this);
    gameGraphics.start();
}

@Override
public void run() {     
    while(gameCore.isRunning() == true){
        if(!surfaceHolder.getSurface().isValid())
            continue;
        Canvas canvas = surfaceHolder.lockCanvas();
        canvas.drawBitmap(player.getImage(), player.getX(), player.getY(), null);
        surfaceHolder.unlockCanvasAndPost(canvas);
    }
}

}

玩家类 -

public Player(GameCore gameCore, Context context) {
    this.gameCore = gameCore;
    this.context = context;
    displayMetrics = new DisplayMetrics();
    gameCore.getWindowManager().getDefaultDisplay().getMetrics(displayMetrics);
    /* INITIALIZE HEIGHT AND WIDTH VARIABLES */
    height = 72;
    width = 72;
    x = (displayMetrics.widthPixels / 2); 
    y = displayMetrics.heightPixels - (height + 5);
    xChange = 0;
    /* INITIALIZE IMAGE */
    image = BitmapFactory.decodeResource(context.getResources(),R.drawable.ic_launcher);
}

***我使用默认的ic_launcher来测试****

相对于屏幕尺寸android绘制图像

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