Question

我收到语法错误，但对我而言似乎是正确的代码，但得到了：

解析错误：语法错误，意外';'在第121行的C：\ xampp \ htdocs \ orlando \ php \ processor \ processor.php

我的代码是：

    $sql_new = mysqli_query($conn, 
        'SELECT * FROM
        products_added
        where username = "'.mysqli_real_escape_string($conn, $_SERVER['REMOTE_ADDR'].'"
        ORDER BY id asc'
    );

Answer 1

您在mysqli_real_escape_string上留下了右括号。

$sql_new = mysqli_query($conn, 
    'SELECT * FROM
    products_added
    where username = "' .mysqli_real_escape_string($conn, $_SERVER['REMOTE_ADDR']) . '"
    ORDER BY id asc'
);

Answer 2

在此行中缺少)：

where username = "'.mysqli_real_escape_string($conn, $_SERVER['REMOTE_ADDR'].'"

应该是：

 where username = "'.mysqli_real_escape_string($conn, $_SERVER['REMOTE_ADDR']).'"

Answer 3

您在查询

中错过了最后)

'SELECT * FROM products_added
 where username = "'.mysqli_real_escape_string($conn, $_SERVER['REMOTE_ADDR']).'"
 ORDER BY id asc'

Answer 4

$sql_new = mysqli_query($conn, 
        'SELECT * FROM
        products_added
        where username = "'.mysqli_real_escape_string($conn, $_SERVER['REMOTE_ADDR']**)**.'"
        ORDER BY id asc'
);

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我得到一个语法错误是我的mysqli_query的PHP代码

4 个答案: