Question

<form action="applications.php" enctype="multipart/form-data" method="post">
Value1: <input type="text" name="value"><br>
Value2: <input type="text" name="value1"><br>
<input type="submit"         onmouseover="this.style.cursor=\'pointer\';"OnMouseOut="this.style.cursor=\'default\';">
 </form>

<?php
if (isset($_GET['value=20'&&'value1=40']))
{
$username = 'root';
$password = '';
$hostname = 'localhost';
$dataname = mysql_connect($hostname,$username,$password) or die("Connection failed: ");
$selected = mysql_select_db('testdb',$dataname) or die("Could not select table1");
$result = mysql_query("SELECT * FROM `table1`");
$last = '';
echo "<table>
    <tr>
        <th>id</th>
        <th>name</th>
    </tr>";
 while($row = mysql_fetch_array($result))
 {
 echo"<tr>
         <td>".$row['0']."</th>
         <td>".$row['1']."</td>
    </tr>"; 
    }
mysql_close($dataname);
}
?>

例如，如果我输入了value1 = 20和value2 = 40，那么我必须得到＆＃34; table1＆＃39;结果。任何人都可以帮我纠正这段代码或者告诉我另一种方法。

Answer 1

你对价值观的警惕是错误的...... if（isset（$ _ GET ['value = 20'＆amp;＆amp;'value1 = 40']））

应该是

if（（isset（$ _ GET ['value']）＆amp;＆amp;（$ _GET ['value'] =='20'）＆amp;＆amp; （isset（$ _ GET ['value2']）＆amp;＆amp;（$ _GET ['value2'] =='40'））

如果给出2个输入值，如何使用php从数据库中获取表？

1 个答案: