Question

我想写一个程序来检查字符串中的每个字符。如果连续两个字符相同，我想将计数增加1.程序应该扫描所有字符并给我们一个值。 T用于决定我们将输入多少个字符串。

例如:(输入）五 AAAA BBBBB ABABABAB BABABA AAABBB

输出继电器 3 4 0 0 4

但我得到0 3 4 0 0

你可以帮忙吗？我做错了什么？

 import java.io.*;
 import java.util.*;
 import java.text.*;
 import java.math.*;
 import java.util.regex.*;

public class Solution
{

   public static void main(String[] args)
   {
       int i,T,j,count;
       String S;
       char K;
       count = 0;
       Scanner scan = new Scanner(System.in);
       T = scan.nextInt(); 
       for (i = 0; i <= T - 1; i++)
       {
           count = 0;
           S = scan.nextLine();
           char[] list = new char[S.length()];
           for(j = 0; j <= S.length() - 1; j++)
           {
               list[j] = S.charAt(j);    
           }
           for(j = 1; j <= S.length() - 1; j++)
           {
              if(list[j - 1] == list[j])
              {
                  count++;
              }     
           }
          System.out.println(count);
       }
   }
}

Answer 1

我认为类似下面的内容可以帮助你，首先需要输入一些字符串，然后在输入的字符串中计算字符与前一个字符相同的次数。它不会采用一系列字符串，它将逐个执行，请参见下面的示例输出：

   public static void main(String[] args){  
       int numInput;
       String inputString;
       Scanner scanner = new Scanner(System.in);
       numInput = scanner.nextInt();

       for(int y = 0; y < numInput;y++){           
           inputString = scanner.next();
           char[] chars = inputString.toCharArray();
           int counter = 0;

           char curr;
           for(int x = 0; x < chars.length;x++){
               curr = chars[x];
             if(x>0){
                if(chars[x-1] == curr){
                    counter++;
                }
             }
           }
           System.out.println("Count for string " + inputString + " was " + counter);
       }
       scanner.close();
   }

测试：

5
AASAAB
Count for string AASAAB was 2
AAAAAA
Count for string AAAAAA was 5
AAVAAD
Count for string AAVAAD was 2
MOOMOO
Count for string MOOMOO was 2
MAAAAAA
Count for string MAAAAAA was 5

Answer 2

试试这个......

public static void main(String[] args) {
    int i, T, j, count;
    String S;
    char K;
    count = 0;
    Scanner scan = new Scanner(System.in);
    T = scan.nextInt();
    for (i = 0; i <= T - 1; i++) {
        scan = new Scanner(System.in);
        count = 0;
        S = scan.nextLine();
        char[] list = new char[S.length()];
        for (j = 0; j <= S.length() - 1; j++) {
            list[j] = S.charAt(j);
        }
        for (j = 1; j <= S.length() - 1; j++) {
            if (list[j - 1] == list[j]) {
                count++;
            }
        }
        System.out.println(count);
    }
}

检查字符串中的字符

2 个答案: