Question

所以我正在用以下场景开发简单的游戏：

2位用户需要开始游戏（因此我为第3位用户创造了新的空间，依此类推）
每个房间最多2位用户
当游戏开始时，事件被发送到客户端，60秒后服务器需要结束游戏。

我编写的代码仅适用于1个房间，但对于多个房间，取消不正确，因为我的lastRoom变量不正确。

我是node.js的新手，所以我不确定如何解决这个问题。

一些代码：

var lastRoom = 'default'; //this is the first created room

function tryToStartGame(socket){

  var clients = io.sockets.adapter.rooms[lastRoom];

  console.log("Size of room "+lastRoom+" is: "+getObjectSize(clients));

  //we are checking size of last room
  if (getObjectSize(clients) == 2){

    //players in the room should be different
    games['default']= {
      'leftPlayer': getFromObject(clients, 0),
      'rightPlayer': getFromObject(clients, 1),
      'stuff': "some data here"
      'roomName': lastRoom
    };

    console.log("We can start the game");

    //let all the people in that room
    io.to(lastRoom).emit('game', games['default']);

    //game to cancel
    gameToCancel = lastRoom;

    //client needs to be aware when game is ended
    //but if we have simultaneous games this will not work
    setTimeout(function(){
      console.log("Cancelling game in: "+gameToCancel);
      io.to(gameToCancel).emit('gameEnded', "Winner logic is todo ;) ");

    }, 8000); //after 8 seconds for test

    //reset the room name, so next time when this function is called in second room
    //we will have something different
    lastRoom = 'game'+new Date().getTime();
  }

  //we have less then 2 players, wait for another player
  if (getObjectSize(clients)<2){
    console.log("Less then 2 players");
    socket.emit('waiting', 'Waiting for another user to join the game');
  }

}

tryToStartGame(socket)函数始终在连接处调用，如下所示：

io.on('connection', function(socket){

  //when client says he wants to play
  socket.on('joinGame', function(username){

    //add user
    addUser(socket, username);

    //send list of players
    io.emit('playersList', getFormatedPlayers());

    //figure out in which room this player bellongs
    socket.join(lastRoom);

    //try to start the game
    tryToStartGame(socket);

  });

有问题的部分是，lastRoom变量被覆盖，然后setTimeout选择了错误的房间，那么基本上最后一个游戏被取消的情况会发生什么，而之前的游戏则没有。

如何在正确的房间内正确跟踪和取消游戏？

Answer 1

如您所述，lastRoom是一个全局变量，可能/将在您设置它和超时之间发生变化

您可以在超时功能上创建一个闭包，以将房间保持为区域设置变量：

var lastRoom = 'default'; //this has to be set in the same function than the call to setTimeout

//client needs to be aware when game is ended
//but if we have simultaneous games this will not work
setTimeout(function(){
  var gameToCancel = lastRoom;

  console.log("Cancelling game in: "+gameToCancel);
  io.to(gameToCancel).emit('gameEnded', "Winner logic is todo ;) ");

}, 8000); //after 8 seconds for test

带有socket.io的node.js中的并发计时器

1 个答案: