Question

您能告诉我代码出了什么问题吗？我尝试在spring mvc的select中遍历对象列表。结果应该是通过getDisplayName（）检索的两个bean的文件串联。但是在jsp中这个方法的结果看起来像是toString（） - org.financespring.model.Client@1aaed9a9的结果。谢谢你的帮助。代码如下：

的.jsp

<body>
    <form:form action="newclientpage" method="post" modelAttribute="client">
        <div id="client-buttons">
            <input type="button" name="client-action" value="Add Client">
            <input type="button" name="client-action" value="Del Client">
            <input type="button" name="client-action" value="Edit Client">
            <input type="button" name="client-action" value="Show client details">
        </div>
        <form:select path="displayName" items="${listOfClients}" size="25" width="200px"/>
    </form:form>
</body>

控制器

@RequestMapping(value = "/", method = RequestMethod.GET)
    public String initNewClientForm(ModelMap model) {
        Client client = new Client();
        List<Client> listOfClients = clientService.getListOfClients();
        model.addAttribute("client", client);
        model.addAttribute("listOfClients", listOfClients);
        return "clientpage";
    }

豆

@Entity
@Table(name = "client")
public class Client extends BaseEntity {

    @Column(name = "first_name", nullable = false)
    private String firstName;

    @Column(name = "last_name", nullable = false)
    private String lastName;

    @Column(name = "address", nullable = false)
    private String address;

    @Column(name = "city", nullable = false)
    private String city;

    @Column(name = "postal_code", nullable = false)
    private String postalCode;

    public String getFirstName() {
        return firstName;
    }

    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }

    public String getLastName() {
        return lastName;
    }

    public void setLastName(String lastName) {
        this.lastName = lastName;
    }

    public String getAddress() {
        return address;
    }

    public void setAddress(String address) {
        this.address = address;
    }

    public String getCity() {
        return city;
    }

    public void setCity(String city) {
        this.city = city;
    }

    public String getPostalCode() {
        return postalCode;
    }

    public void setPostalCode(String postalCode) {
        this.postalCode = postalCode;
    }

    public String getDisplayName() {
        return firstName + " " + lastName;
    }
}

Answer 1

您需要遍历您的客户端列表并创建一个仅包含显示名称的新列表，然后将此列表用于jsp文件中的select。

List<String> displayNames = new ArrayList<String>();
for(Client c : listOfClients)
    displayNames.add(c.getDisplayName());
model.addAttribute("listOfDisplayNames", displayNames);

Answer 2

您可以像这样添加列表：

<form:select path="displayName">
    <form:options items="${listOfClients}" itemValue="displayName" itemLabel="displayName" />
</form:select>

弹簧形式：选择cat作为toString

2 个答案: