NamingException:无法使用tomcat7-maven-plugin h2 / mysql数据库创建资源实例

时间:2014-12-23 13:23:10

标签: mysql maven tomcat7 h2 tomcat-jdbc

我试图创建maven web应用程序项目,在打包时创建独立的可执行jar,为此我使用tomcat7-maven-plugin。最初的hello world应用程序工作正常,但我努力使它与数据库一起工作。 这是我的pom.xml的样子:

<plugin>
<groupId>org.apache.tomcat.maven</groupId>
<artifactId>tomcat7-maven-plugin</artifactId>
<version>2.0</version>
<executions>
    <execution>
        <id>tomcat-run</id>
        <goals>
            <goal>exec-war-only</goal>
        </goals>
        <phase>package</phase>
        <configuration>
            <contextFile>src/main/resources/tomcat/context.xml</contextFile>
            <path>/helloworld</path>
            <enableNaming>true</enableNaming>
            <finalName>standalone.jar</finalName>
            <charset>utf-8</charset>
        </configuration>
    </execution>
</executions>
<dependencies>
    <dependency>
        <groupId>com.h2database</groupId>
        <artifactId>h2</artifactId>
        <version>1.4.183</version>
    </dependency>
    <dependency>
        <groupId>mysql</groupId>
        <artifactId>mysql-connector-java</artifactId>
        <version>5.1.34</version>
    </dependency>
</dependencies>

的src /主/ web应用/ WEB-INF / web.xml中:

<web-app>
...
<servlet>
        <servlet-name>TestServlet</servlet-name>
        <servlet-class>com.mycompany.test.TestServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>TestServlet</servlet-name>
        <url-pattern>/helloworld</url-pattern>
    </servlet-mapping>
    <resource-ref>
        <description>H2 DS</description>
        <res-ref-name>jdbc/H2DB</res-ref-name>
        <res-type>org.apache.tomcat.jdbc.pool.DataSource</res-type>
        <res-auth>Container</res-auth>
    </resource-ref>
    <resource-ref>
        <description>Mysql DS</description>
        <res-ref-name>jdbc/TestDB</res-ref-name>
        <res-type>org.apache.tomcat.jdbc.pool.DataSource</res-type>
        <res-auth>Container</res-auth>
    </resource-ref>
...
</web-app>

的src /主/资源/ Tomcat的/ context.xml中

<Context path="/helloworld">
    <Resource type="org.apache.tomcat.jdbc.pool.DataSource"
        name="jdbc/H2DB"
        factory="org.apache.tomcat.jdbc.pool.DataSourceFactory"
        driverClassName="org.h2.Driver"
        url="jdbc:h2:mem:testdb;DB_CLOSE_DELAY=-1"
        username="testuser"
        password="testpassword"
        initialSize="5"
        maxActive="10"
        maxIdle="5"
        minIdle="2"
    />
    <Resource name="jdbc/TestDB" auth="Container" type="org.apache.tomcat.jdbc.pool.DataSource"
        url="jdbc:mysql://localhost:3306/testdb"
        username="testuser" 
        password="testpassword" 
        driverClassName="com.mysql.jdbc.Driver"
        initialSize="5"
        maxActive="10"
        maxIdle="5"
        minIdle="2"
    />
</Context>

在我的java代码中我尝试了:

Context ctx = new InitialContext();
DataSource ds = (DataSource) ctx.lookup("java:/comp/env/jdbc/TestDB");
h2数据库的

或java:/ comp / env / jdbc / H2DB 当tomcat启动我的servlet时,我以两种方式获得相同的异常:

  

严重:Servlet / helloworld抛出了load()异常   javax.naming.NamingException:无法创建资源实例           at org.apache.naming.factory.ResourceFactory.getObjectInstance(ResourceFactory.java:146)           在javax.naming.spi.NamingManager.getObjectInstance(未知来源)           在org.apache.naming.NamingContext.lookup(NamingContext.java:843)           在org.apache.naming.NamingContext.lookup(NamingContext.java:154)           在org.apache.naming.NamingContext.lookup(NamingContext.java:831)           在org.apache.naming.NamingContext.lookup(NamingContext.java:154)           在org.apache.naming.NamingContext.lookup(NamingContext.java:831)           ...

我会对任何想法表示感谢。 提前谢谢。

1 个答案:

答案 0 :(得分:0)

通过添加mysql-connector-java来解决问题,如here所描述的tomcat7-maven-plugin的配置。