我有这段代码:
$gendate = new DateTime();
$gendate->setISODate(2014,52,4);
echo $gendate->format('d-m-Y');
我想在核心PHP中编码,因为我是PHP的新手。我希望你能得到我想要的东西吗?
答案 0 :(得分:0)
当我理解你的时候
试试这个
$time = strtotime("1 January $year", time());
$day = date('w', $time);
$time += ((7*$week)+1-$day)*24*3600;
$dates[0] = date('Y-n-j', $time);
$time += 6*24*3600;
$dates[1] = date('Y-n-j', $time);
var_dump($dates);