我想从image_preview找到一种方法,将dom作为参数并获取数据。
并且单独的image_preview.model()
和image_preivew.on_chage()
是事件处理程序
使image_preview可重复使用而不是内部硬编码
我认为我会在参数中调用image_preview
传递dom,并将src作为响应返回,然后我可以使用repsponse执行类似追加...
var image_preview = {
on_change: function(wrap_dom, input_dom) {
$(wrap_dom).on('change', input_dom, function(event) { // I have to use on change because there are possible the `input dom` is new append...
var el_obj = $(this)[0];
var form_data = new FormData();
var file_length = el_obj.files.length;
for (var i = 0; i < file_length; i++) {
form_data.append("file[]", el_obj.files[i]);
}
image_preview.model(form_data).done(function(response) {
// console.log(response); // this is work
return response;
});
});
},
model: function(form_data) {
return $.ajax({
url: uri_public+'/admin/ajax/preview_file',
type: 'POST',
data: form_data,
processData: false,
contentType: false,
// async: false
});
}
}
var app_thumbnail = {
preview_controller: function() {
var wrap_dom = '.thumbnail';
var input_dom = '.upload-form input';
var result = image_preview.on_change(wrap_dom, input_dom);
// pass result to render view like append dom....
},
render: function() {
},
}
app_thumbnail.preview_controller();
答案 0 :(得分:0)
这是您可以做的最简单的事情:
var image_preview = {
on_change: function(wrap_dom, input_dom) {
$(wrap_dom).on('change', input_dom, function(event) {
var el_obj = $(this)[0];
var form_data = new FormData();
var file_length = el_obj.files.length;
for (var i = 0; i < file_length; i++) {
form_data.append("file[]", el_obj.files[i]);
}
image_preview.model(form_data).done(function(response) {
app_thumbnail.preview_controller(response);
});
});
},
model: function(form_data) {
return $.ajax({
url: uri_public+'/admin/ajax/preview_file',
type: 'POST',
data: form_data,
processData: false,
contentType: false,
// async: false
});
}
}
var app_thumbnail = {
preview_controller: function(response) {
var wrap_dom = '.thumbnail';
var input_dom = '.upload-form input';
var result = response;
}
}
// If you want to initialize it.
// image_preview.on_change(..., ...);