+---+------------+
|sid| discounts |
+---+------------+
| 1 | 10.00 |
| 2 | 20.00 |
2 | 20.00 |
+---+------------+
我需要获得列折扣的总和,但是如果列sid具有相同的值,则只添加一行而不是全部。
所以我需要说30.00而不是50.00
我试过这样的事情
SELECT DISTINCT sid FROM (SELECT SUM(discounts) FROM $table_name)
和
SELECT SUM(discounts) FROM $table_name WHERE sid IN (SELECT DISTINCT 'sid' FROM $table_name)
我刚刚收到您的SQL语法错误'
答案 0 :(得分:2)
如果您删除single quuto betwwen sid
SELECT SUM(discounts) FROM $table_name WHERE sid IN (SELECT DISTINCT sid FROM $table_name)
答案 1 :(得分:0)
select sum(discounts) from (select discounts,sid from $table_name group by sid) t
答案 2 :(得分:0)
我希望这会起作用
$sql=mysql_query("select SUM(discounts) from table_name groub by sid");
答案 3 :(得分:0)
它很简单,你可以使用
select SUM(discount) from (SELECT discount FROM `table_name` group by sid) as discount
希望这对您有用
答案 4 :(得分:0)