我正在尝试从一系列承诺中获取一系列结果。 我能够通过我没有获得结果数组来定义承诺数组 以下是我的代码
function get_order_selection(order){
var itemList=[];
var promise = Parse.Promise.as();
var query = new Parse.Query("Order_Selection");
query.equalTo("order", order);
query.include('wine');
promise = query.find().then(function(results) {
console.log("Order_Selection received for order.id: " + order.id + " result(s): " +results.length);
console.log(results);
var i = 0;
var size = results.length;
while(i<size){
var name = results[i].get('wine').get('name');
var unitPrice = results[i].get('unitPrice');
var quantity = results[i].get('quantity');
var smallURL = results[i].get('wine').get('small_picture').url();
console.log("Order_Selection-> name: "+name+ " unitPrice: "+unitPrice+" quantity: "+quantity+" smallURL: "+smallURL);
var item = {
name: name,
unitPrice: unitPrice,
quantity: quantity,
smallURL: smallURL
}
itemList.push(item);
i++;
}
console.log("get_order_selection: itemList:"+itemList);
return itemList;
});
return promise;
}
在我的主要电话中
var i = 0;
var size = results.length;
while(i<size){
selection_query.push(get_order_selection(results[i]));
i++;
}
我无法在阵列中得到结果。
Parse.Promise.when(selection_query).then(
function(results,results2,results3){
console.log("Promise results");
console.log("Promise results.length:"+results.length);
console.log("Promise results2.length:"+results2.length);
var responseJSON = {orders: orders_list};
response.success(responseJSON);
}
);
答案 0 :(得分:1)
我找到了答案。 的console.log(&#34;的arguments.length:&#34 +的arguments.length);
使用参数。
Parse.Promise.when(selection_query).then(
function(results,results2,results3){
console.log("arguments.length:"+arguments.length);
console.log("Promise results");
console.log("Promise results.length:"+results.length);
console.log("Promise results2.length:"+results2.length);
var responseJSON = {orders: orders_list};
response.success(responseJSON);
}
);