javascript日期差异NaN

Question

在下面的代码中我得到了course_diff_date作为NaN我在这里做错了什么，我想在天里得到差异

console.log(d1);
//Thu Jan 01 1970 05:30:00 GMT+0530 (IST)
var today = new Date(); 
var course_time = new Date(d1);
var new_date = new Date(today.getMonth()+ "/" +today.getDate()+ "/" +today.getFullYear());
var server_date = new Date(course_time.getMonth()+ "/" +course_time.getDate()+ "/" +course_time.getFullYear());
var timeDiff = Math.round(new_date.getTime() - server_date.getTime());
var diffDays = Math.ceil(timeDiff / (1000 * 3600 * 24));
course_diff_date = diffDays + " Days";

Answer 1

请尝试使用date.getTime()：

修改

var daysTillNow = function(str) {
  var today = new Date();
  //time stamp is taken for testing
  var course_time = new Date(str);
  //difference in mili seconds
  var diff = today.getTime() - course_time.getTime();
  //round off mili-sec to days
  diff = Math.round(diff / (1000 * 60 * 60 * 24));
  return diff + " day(s)";
};


console.log(daysTillNow('Thu Dec 11 2014 05:30:00 GMT+0530 (IST)')); //11 days
console.log(daysTillNow('Mon Dec 22 2014 11:13:21 GMT+0530 (IST)')); //0 days

open console... F12

Answer 2

而不是

course_time.time.getMonth()

使用：

course_time.getMonth()

Answer 3

你有额外的.time

var server_date = new Date(course_time.time.getMonth()+ "/" +course_time.getDate()+ "/" +course_time.getFullYear());

应该是

var server_date = new Date(course_time.getMonth()+ "/" +course_time.getDate()+ "/" +course_time.getFullYear());

Answer 4

应该是course_time而不是course_time.time

d1 = "12 January 2014";
d1 = new Date(d1);
var today = new Date(); 
var course_time = new Date(d1);
var new_date = new Date(today.getMonth()+ "/" +today.getDate()+ "/" +today.getFullYear());
var server_date = new Date(course_time.getMonth()+ "/" +course_time.getDate()+ "/" +course_time.getFullYear());
var timeDiff = Math.round(new_date.getTime() - server_date.getTime());
var diffDays = Math.ceil(timeDiff / (1000 * 3600 * 24));
course_diff_date = diffDays + " Days";