Question

我已经阅读了几个小时和几个小时来弄清楚如何对String[]进行排序和按字母顺序排列，但是因为我从我的手机Contacts中取出并且整个ListView是Fragment 1}}，没有什么可以真正解决我的情况。我必须在我的CursorAdapter中使用String[]，并且一些字母顺序教程使用其他适配器，所以我无法弄明白。

如果您知道使用我已有的代码对String[]进行排序/字母排序的一种非常简单的方法（考虑使用ListView，Fragment附带的所有细节，以及从Contacts拉出来，我将非常感激。目前此代码有效，但它会提取未排序的联系人。

感谢您的建议。

ContactsFragment.java

package com.example.practiceapp.addressbook;

import java.util.ArrayList;
import java.util.Arrays;

import android.app.ListFragment;
import android.app.LoaderManager.LoaderCallbacks;
import android.content.CursorLoader;
import android.content.Loader;
import android.database.Cursor;
import android.net.Uri;
import android.os.Bundle;
import android.provider.ContactsContract;
import android.provider.ContactsContract.Contacts;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.CursorAdapter;
import android.widget.ListView;
import android.widget.SimpleCursorAdapter;

import com.example.practiceapp.R;

/*
 * Taken from http://stackoverflow.com/questions/18199359/how-to-display-contacts-in-a-listview-in-android-for-android-api-11
 */

public class ContactsFragment extends ListFragment implements 
                                LoaderCallbacks<Cursor>{

    private CursorAdapter mAdapter;
    public ListView listView;
    // Name should be displayed in the text1 TextView in item layout
    public static String[] from = { ContactsContract.Contacts.DISPLAY_NAME_PRIMARY };
    private static final int[] TO = { android.R.id.text1 };
    private android.content.Context context;
    ArrayList<String> elements;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        // create adapter once
        context = getActivity();
        int layout = android.R.layout.simple_list_item_1;
        Cursor c = null; // there is no cursor yet
        int flags = 0; // no auto-requery! Loader requeries.

        Arrays.sort(from);

        // put List in adapter
        mAdapter = new SimpleCursorAdapter(context, layout, c, from, TO, flags);

    }

    // columns requested from the database
    private static final String[] PROJECTION = {
            Contacts._ID,
            ContactsContract.Contacts.DISPLAY_NAME_PRIMARY
    };

    // Empty public constructor, required by the system
    public ContactsFragment() {}

    // A UI Fragment must inflate its View (all fragments must override onCreateView)
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
            Bundle savedInstanceState) {
        // Inflate the fragment layout
        View view =  inflater.inflate(R.layout.contact_list_view,
            container, false);
        listView = (ListView) view.findViewById(R.id.list); 
        return view;
    }

    public void onActivityCreated(Bundle savedInstanceState) {
        super.onActivityCreated(savedInstanceState);

        // and tell loader manager to start loading
        getLoaderManager().initLoader(0, null, this);

        listView.setAdapter(mAdapter);
        listView.setFastScrollEnabled(true);

    }

    @Override
    public Loader<Cursor> onCreateLoader(int id, Bundle args) {
        // load from the "Contacts table"
        Uri contentUri = Contacts.CONTENT_URI;

        // no sub-selection, no sort order, simply every row
        // projection says we want just the _id and the name column
        return new CursorLoader(getActivity(),
                contentUri,
                PROJECTION,
                null,
                null,
                null
        );
    }

    @Override
    public void onLoadFinished(Loader<Cursor> loader, Cursor data) {
         // Once cursor is loaded, give it to adapter
        mAdapter.swapCursor(data);
    }

    @Override
    public void onLoaderReset(Loader<Cursor> loader) {
        // Delete the reference to the existing Cursor,
        // so it can recycle it
        mAdapter.swapCursor(null);

    }
}

Answer 1

CursorLoader构造函数的最后一个参数是排序顺序。它使用与普通SQL ORDER BY子句相同的语法。

在片段中按字母顺序排序并对String []数组（来自Contacts）进行排序

1 个答案: