Question

这又是THIS的扩展排名。

我更改了我的表格式，我的意思是我为vendor_locations创建了一个单独的表，其中我在多行中针对该供应商ID存储了多个位置。并创建了一个表vendor_products来存储该供应商的多个产品。

现在我的问题是，由于每个供应商的产品和位置都是多个，而显示我没有得到如何在一行中显示它。

如果产品为3且位置为2，则所有细节将显示三次。如果我删除任何位置或产品，它将正常工作。但我怎么能为这两个

做这个

 if(isset($_POST['submit']))
{
$sql="SELECT vendor.id AS venid
, vendor.name AS VNAME
, vendor.category
, vendor.website
, vendor.email
, vendor.phone
, vendor.vat
, vendor.pan
, items.name AS iname
, location.name AS locname 
, items.item_id
FROM vendor 
    INNER JOIN vendor_location ON vendor.id = vendor_location.vendor_id 
    INNER JOIN vendor_products ON vendor.id=vendor_products.vendor_id 
    INNER JOIN location ON vendor_location.location = location.loc_id 
    INNER JOIN items ON vendor_products.item_id=items.item_id 
    ORDER BY vendor.id";

}

$sql1 = mysql_query($sql) or die(mysql_error());
} 

?>
<div class="w-box w-box-blue">
                            <div class="w-box-header">
                                <h4>Vendor</h4>
                            </div>
                            <div class="w-box-content"> 

    <table id="dt_hScroll" class="table table-striped">
                        <thead><tr>
                        <th>Vendor ID</th>
                        <th>Vendor</th>
                        <th>Category</th>
                        <th>Website</th>
                        <th>Email</th>
                        <th>Phone</th>

                        <th>VAT</th>
                        <th>PAN</th>
                        <th>Products</th>
                        <th>Locations</th>




</tr>

</thead>
<tbody> 


<?php
$current = '';            // STORE THE SUPPLIER SID
    while($row = mysql_fetch_array($sql1)) {
        if ($row['venid'] != $current) {
            echo "<tr>
                <td><a href='edit_vendor_details.php?id=$row[venid]'>{$row['venid']}</a></td>
                <td>{$row['VNAME']}</td>
                <td>{$row['category']}</td>
                <td>{$row['website']}</td>
                <td>{$row['email']}</td>
                <td>{$row['phone']}</td>
                <td>{$row['vat']}</td>
            <td>{$row['pan']}</td>
                ";
            $current = $row['venid'];   // RESET  STORED SID
        }
        else {
            echo "<tr><td colspan='8'>&nbsp;</td>";
        }

        echo "<td>{$row['iname']}</td>";
        echo "<td>{$row['locname']}</td>";


         echo "</tr>";
    }
    echo('</tbody></table>');


?>
</tbody></table>

Answer 1

如果您只想显示，请在字段上使用group_concat。像这样：

SELECT vendor.id AS venid --rest of selection
    , GROUP_CONCAT(location.name) AS locname 
    , GROUP_CONCAT(items.item_id)
FROM vendor --rest of your joins
GROUP BY vendor.id

在此处详细了解：MySQL Aggregate Functions

显示包含多个结果的数据

1 个答案: