Question

当我运行mysql_num_rows查询以检查用户名是否已在我的php文件中注册时，收到错误。

Warning: mysql_num_rows() expects parameter 1 to be resource, string given
  in C:\xampp\htdocs\system\class.database.php on line 22

这是我的代码......首先是我的nameTaken函数，我运行行函数...

public function nameTaken($username)
{
    global $database;
    if ($database->rows("SELECT COUNT(*) FROM users WHERE username = '" . $username . "' LIMIT 1") > 0)
    {
        return true;
    }

    return false;
}

以下是我在数据库类中的连接方式

public function connect()
{
    global $config;
    $this->connection = mysql_connect($config['db']['host'], $config['db']['user'], $config['db']['pass']);
    mysql_select_db($config['db']['name'], $this->connection);
}

这是行函数

public function rows($command)
{
    echo 'ROWS IS BEING CALLED BY ' . $command;
    $result = mysql_query($command);
    $rows = mysql_num_rows($command);
    return $rows;
}

为什么我在运行mysql_num_rows时收到错误？

Answer 1

您需要将结果资源传递给mysql_num_rows。将$rows = mysql_num_rows($command);更改为$rows = mysql_num_rows($result);

mysql_num_rows（）期望参数1是资源，给定字符串

1 个答案: