Question

我有一个区域计算器，我希望用户在开始时选择要计算的东西，而不是在列表中。是否有用于询问用户的代码，并停止其他代码。在用户选择之后，将用户带到该特定功能。然后，把他们带回问题屏幕？需要一些建议。

import math

def square():
    print ("Area of Square")
    print ("")
    S = float(input("Enter Length of Square:"))
    A = round((S**2),3)
    print (A, "is the Area of the Square")
    print("")
    print("")
square()

def rectangle():
    print("Area of Rectangle")
    print ("")
    L = float(input("Enter Length of Rectangle:"))
    W = float(input("Enter Width of Rectangle:"))
    A = round((L*W),3)
    print (A, "is the Area of the Rectangle")
    print("")
    print("")
rectangle()

def paralelogram():
    print("Area of Paralelogram")
    print("")
    B = float(input("Enter Base of Paralelogram:"))
    H = float(input("Enter Height of Paralelogram:"))
    A = round((B*H),3)
    print (A, "is the Area of the Paralelogram")
    print("")
    print("")
paralelogram()

def triangle():
    print("Area of Triangle")
    print("")
    B = float(input("Enter Base of Triangle:"))
    H = float(input("Enter Height of Triangle:"))
    A = round(((B*H)/2),3)
    print (A, "is the Area of the Triangle")
    print("")
    print("")
triangle()

def circle():
    print("Area of Circle")
    print("")
    r = float(input("Enter Radius of Circle:"))
    A = round(math.pi*(r**2),3)
    print (A, "is the Area of the Circle")
    print("")
    print("")
circle()

def trapezoid():
    print("Area of Trapezoid")
    print("")
    B1 = float(input("Enter Base 1 of Trapezoid:"))
    B2 = float(input("Enter Base 2 of Trapezoid:"))
    H = float(input("Enter Height of Trapezoid:"))
    A = round((((B1+B2)/2)*H),3)
    print (A, "is the Area of the Trapezoid")
    print("")
    print("")
trapezoid()

def sphere():
    print("Area of Sphere")
    print("")
    r = float(input("Enter Radius of Sphere:"))
    A = round((((r**2)*4)*math.pi),3)
    print (A, "is the Area of the Sphere")
    print("")
sphere()

Answer 1

更多Pythonic的方法是在字典中存储对函数的引用：

area_func = {'triangle': triangle, 'square': square, 'rectangle': rectangle,
             'paralelogram': paralelogram, 'circle': circle, 'trapezoid': trapezoid,
             'sphere': sphere}

while True:
    shape = input('What shape do you want to calculate the area of ("stop" to end)?')
    if shape == 'stop':
        break
    try:
        area_func[shape]()
    except KeyError:
        print("I don't recognise that shape.")
        continue

这很有效，因为函数和Python中的其他函数一样，都是对象。因此，您可以将它们作为值存储在字典中，为它们分配变量名等。表达式area_func[shape]因此是对函数的引用，例如triangle，然后可以调用它（通过附加()，一组空括号，因为你的函数不带任何参数。）

正如其他人所说，你可能不希望在每个定义之后调用函数。并且，为了迂腐，平行四边形是正确的拼写。

Answer 2

你可以用while循环来做到这一点。

#your functions here

options="""1-)Square
2-)Rectangel
3-)Paralelogram
4-)Triangle
5-)Trapezoid
6-)sphere
"""
while True:
    print (options)
    user=input("Please choose a valid option: ")
    if user=="1":
        square()
        continue
    elif user=="2":
        rectangel()
        continue
    ..
    ..
    ..  #same codes with elif statement till 6.
    ..
    else:
        print ("It's not a valid choose.Please choose a valid one.")

询问用户他们想要什么样的功能

2 个答案: