我怎样才能抓住这个例外:
com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException:
Duplicate entry '22-85' for key 'ID_CONTACT'
答案 0 :(得分:22)
我使用spring,所以我们通过org.springframework.dao.DataIntegrityViolationException
try {
ao_history_repository.save(new AoHistory(..));
}
catch (DataIntegrityViolationException e) {
System.out.println("history already exist");
}
答案 1 :(得分:8)
catch SQLIntegrityConstraintViolationException ,如果您使用的是Java 1.6 +
e.g。
try {
ps.executeUpdate("INSERT INTO ...");
} catch (SQLIntegrityConstraintViolationException e) {
// Duplicate entry
} catch (SQLException e) {
// Other SQL Exception
}
或
try {
ps.executeUpdate("INSERT INTO ...");
} catch (SQLException e) {
if (e instanceof SQLIntegrityConstraintViolationException) {
// Duplicate entry
} else {
// Other SQL Exception
}
}
答案 2 :(得分:1)
以下是我用来记录SQL Exceptions的内容,以便我可以确定要捕获的内容;
private static void handleSQLError(SQLException e) throws SQLException {
log.info("SQL Error Type : " + e.getClass().getName());
log.info("Error Message : " + e.getMessage());
log.info("Error Code : " + e.getErrorCode());
log.info("SQL State : " + e.getSQLState());
throw e;
}
以下是输出示例;
2018 Nis 05 11:20:32,248 INFO MySQLUtil: SQL Error Type : com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException
2018 Nis 05 11:20:32,248 INFO MySQLUtil: Error Message : Duplicate entry 'test2 CAMT052' for key 'customer_file_customer_file_name_idxu'
2018 Nis 05 11:20:32,249 INFO MySQLUtil: Error Code : 1062
2018 Nis 05 11:20:32,249 INFO MySQLUtil: SQL State : 23000
com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException: Duplicate entry 'test' for key 'customer_file_customer_file_name_idxu'
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:62)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:45)
at java.lang.reflect.Constructor.newInstance(Constructor.java:422)
要捕获重复键Exception,我们需要捕获MySQLIntegrityConstraintViolationException
的特定类。以下参数也必须匹配;
SQL State : 23000
所以我使用以下块来捕获重复的条目;
try {
dbUtil.persistEntry(entry);
} catch (SQLException e) {
if(e instanceof MySQLIntegrityConstraintViolationException) {
if(e.getSQLState().equals("23000")) {
if(e.getMessage().contains("Duplicate")) {
isDuplicateEntryError = true;
}
}
}
}
答案 3 :(得分:1)
vendorCode 2601
是针对unique index constraint
的违反,因此您可以通过e.getErrorCode() == 2601
检查SQLException cewndorCode。示例代码:
try {
ao_history_repository.save(new AoHistory(..));
} catch (SQLException e) {
if (e.getErrorCode() == 2601) {
System.out.println("handle duplicate index error here!");
} else {
System.out.println("handle other error code here!");
}
}
答案 4 :(得分:1)
在我的Spring项目中,引发的异常是org.springframework.orm.jpa.JpaSystemException: org.hibernate.exception.ConstraintViolationException: could not execute statement; nested exception is javax.persistence.PersistenceException: org.hibernate.exception.ConstraintViolationException: could not execute statement
。
因此,在调试之后,我有一个原因为JpaSystemException
的父级PersistenceException
,而原因为ConstraintViolationException
,这最后一个有特定于数据库的异常,但是我最终捕获了{{ 1}}与
ConstraintViolationException
请注意,尽管这可行。 我建议通过在保存之前发出findBy来解决问题,因为这很麻烦,而且我认为不保证它可以在将来的版本中使用,甚至可能在没有通知的情况下中断。
答案 5 :(得分:0)
以下代码适用于我:
try {
requete.executeUpdate();
} catch (final ConstraintViolationException e) {
}
答案 6 :(得分:0)
我同意,但是我们的Spring Application中有这样的内容: RequestValidationException / MessageConstants是自定义的:
import org.springframework.dao.DuplicateKeyException;
|
|
|
catch (Exception exception) {
if(exception instanceof DuplicateKeyException) {
logger.error("exception as duplicate Name Found: " + exception.getMessage());
throw new RequestValidationException(MessageConstants.DUPLICATE_NAME_FOUND_ERROR_CD, MessageConstants.DUPLICATE_NAME_FOUND_ERROR_MSG);
}else{
logger.error("exception on update: " + exception.getMessage());
throw exception;
}
}
答案 7 :(得分:0)
查看Spring框架source code 查看spring JDBC错误解决代码。
org.springframework.jdbc.support.SQLErrorCodeSQLExceptionTranslator#doTranslate
else if (Arrays.binarySearch(this.sqlErrorCodes.getDuplicateKeyCodes(), errorCode) >= 0)
{ logTranslation(task, sql, sqlEx, false); return new DuplicateKeyException(buildMessage(task, sql, sqlEx), sqlEx); }
您可以通过多种方式来使用不同的异常翻译器:
因此Dublicate行为可能会从DuplicateKeyException更改为DataIntegrityViolationException。
答案 8 :(得分:-2)
这个答案来自this
can't get response status code with JavaScript fetch
fetch(`${baseUrl}api/user/login`, {
withCredentials: true,
headers: myHeaders
})
.then(function (response) {
if (response.status !== 200) {
//throw the error from here to next promise if response doesn't success.
throw new Error(response.status);
} else {
//if sucess, the response send to the next promise.
return response.json();
}
})
.then(function (json) {
//get your success data here
dispatch(setLoginInfo(json))
}).catch(err => {
//you can catch the error code here now
console.log(err);
});