Question

我有以下json格式数据：

{"query":{
  "count":5,"created":"2014-12-19T15:42:41Z","lang":"en-US","results":{
    "channel":[{
      "item":{
        "forecast":{"date":"19 Dec 2014","high":"61","low":"47"}
       }},{
      "item":{
        "forecast":{"date":"20 Dec 2014","high":"60","low":"48"}
       }},{
      "item":{
        "forecast":{"date":"21 Dec 2014","high":"61","low":"44"}
       }},{
      "item":{
        "forecast":{"date":"22 Dec 2014","high":"58","low":"46"}
       }},{
      "item":{
        "forecast":{"date":"23 Dec 2014","high":"58","low":"45"}
       }}]
     }
   }
}

如何从这种格式访问特定数据（例如只有高和低），以便将这些数据插入到mySQL数据库中？

Answer 1

例如，将json放在变量$str中，而不是访问项目：

$json = json_decode($str);
$res = $json->{'query'}->{'results'}->{'channel'};
foreach($res as $ch) {
    echo "High:" . $ch->{'item'}->{'forecast'}->{'high'} . "<br>";
    echo "Low:" . $ch->{'item'}->{'forecast'}->{'low'} . "<br>";
}

Answer 2

使用json_decode将其转换为数组：

$array = json_decode($json_data, true);

然后，您可以访问项目，预测和高/低值：

$high = $array[1]['item']['forecast']['high'];

Answer 3

假设你的json字符串是变量$ json：

$data = json_decode($json);
$channels = $data->query->results->channel;
foreach($channels as $channel) {
    // DO SOMETHING HERE
    die($channel["item"]["high"]);
}

从json格式中提取特定数据

3 个答案: