Question

我一直在尝试使用带有codeigniter的datatables jquery插件，但仍然没有运气。我是这个api的新手。（请不要点燃表，只需要dataTables jquery插件）。

视图返回：

未定义的表格数据

请参阅下面的MVC：

VIEW（包含脚本的地方）

<script type="text/javascript">
    $(document).ready(function() {
var oTable = $('#big_table').dataTable( {
    "bProcessing": true,
    "bServerSide": true,
    "sAjaxSource": "<?php echo site_url('home/calendarListAll/') ?>",
            "bJQueryUI": true,
            "sPaginationType": "full_numbers",
            "iDisplayStart ":20,
            "fnInitComplete": function() {
            //oTable.fnAdjustColumnSizing();
     },
            'fnServerData': function(sSource, aoData, fnCallback)
        {
          $.ajax
          ({
            'dataType': 'json',
            'type'    : 'POST',
            'url'     : sSource,
            'data'    : aoData,
            'success' : fnCallback
          });
        }
        } );
    } );
    </script>

    <html>
    <?php echo $this->table->generate(); ?> //this returns "Undefined table data"
    </html>

CONTROLLER

function __construct()
{
 parent::__construct();
  $this->load->library('Datatables');
  $this->load->library('table');
  $this->load->database();
  $this->load->helper('url');
  $this->load->helper('form');
  $this->load->helper('html');
}

public function calendarListAll()
{
    $this->load->model('counselor');
    $result = $this->counselor->getCalendar();
    echo $this->datatables->generate($result);
}

MODEL

function getCalendar() // get referred_appointments
{

    $counselor_id = $this->session->userdata('counselor_id');

    $query = $this->db->select ('s.first_name as student_fname, s.last_name as student_lname, s.middle_name as student_mname, e.first_name, e.last_name, e.middle_name, re.*, r.student_id, i.*, e.*')
    ->from ('referral as r, student_course_record as scr, curriculum as c, referred_appointment as re, degree as d, course as cc, counselor as ccc,  issue as i, student as s, employee as e')
    ->where ('r.student_id = scr.student_id')
    ->where ('scr.curr_id = c.curr_id')
    ->where ('c.degree_id = d.degree_id')
    ->where ('d.course_id = cc.course_id')
    ->where ('cc.counselor_id = ccc.counselor_id')
    ->where ('r.issue_id = i.issue_id')
    ->where ('r.student_id = s.student_id')
    ->where ('re.referral_id = r.referral_id')
    ->where ('r.employee_id = e.employee_id')
    ->where ('ccc.counselor_id', $counselor_id)
    ->where ('re.status != "C"');
    $ret = $query->get()->result();
    return $ret;

}

Answer 1

使用可能会对您有所帮助CI Help

$tmpl = array ('table_open' => '<table id="big_table">');
$this->table->set_template($tmpl);

Answer 2

忘记在生成中传递数据 $这 - ＆GT;表 - ＆GT;生成（$记录）;

使用数据表jquery的codeigniter中的“未定义的表数据”

2 个答案: