根据lastmodified column比较两个表?

时间:2014-12-19 09:58:38

标签: php mysql

我使用此查询按月和年检查票证组

SELECT 
    MONTH((lastmodified)) as month, 
    YEAR((lastmodified)) as year,
    COUNT(num_of_tickets) as tickets
    FROM visitors_2013
    GROUP BY 
    MONTH((lastmodified)), 
    YEAR((lastmodified))

返回类似

的内容
Array
(
    [0] => Array
        (
            [month] => 1
            [year] => 2013
            [tickets] => 1521
        )

    [1] => Array
        (
            [month] => 2
            [year] => 2013
            [tickets] => 513
        )

    [2] => Array
        (
            [month] => 12
            [year] => 2012
            [tickets] => 146
        )

)

我把它放在php函数中,这样我就可以每年获取数据(数据每年存储在一个单独的表中)。 我在2013年和2014年两次调用函数get_ticket_per_year($ year)

Array
(
    [0] => Array
        (
            [month] => 1
            [year] => 2013
            [tickets] => 1521
        )

    [1] => Array
        (
            [month] => 2
            [year] => 2013
            [tickets] => 513
        )

    [2] => Array
        (
            [month] => 12
            [year] => 2012
            [tickets] => 146
        )

)

Array
(
    [0] => Array
        (
            [month] => 12
            [year] => 2013
            [tickets] => 26
        )

)

我想通过在图表中绘制每年每月的数据来比较另一个表(visitor_2014)的月份总票数。为此,我使用morris js库。 这是我需要的结果

data: [ {
            m: 'dec',
            2012: 146,
            2013: 26
        }, {
            m: 'jan',
            2013: 1521,
            2014: 
        }],

那么如何将mysql查询结合起来以便进行一次查询

SELECT 
prevTbl.MONTH((lastmodified)) as prev_month, 
prevTbl.YEAR((lastmodified)) as prev_year,
prevTbl.COUNT(num_of_tickets) as prev_tickets,
currTbl.MONTH((lastmodified)) as curr_month, 
currTbl.YEAR((lastmodified)) as curr_year,
currTbl.COUNT(num_of_tickets) as curr_tickets
FROM visitors_2013 prevTbl, visitors_2014 currTbl 
GROUP BY 
MONTH((lastmodified)), 
YEAR((lastmodified))

1 个答案:

答案 0 :(得分:1)

加入您的疑问:

SELECT * FROM ( [your first query here] ) AS data1
LEFT JOIN ( [your second query here] ) AS data2
ON [your relation between the two query here]

在您的情况下(未经测试):

SELECT * FROM (

    SELECT
        `num_of_tickets` AS `tickets2013`,
        MONTH(`lastmodified`) AS `month`
    FROM `visitors_2013`
    GROUP BY 
        MONTH(`lastmodified`)

) AS `data2013`
LEFT JOIN (

    SELECT
        `num_of_tickets` AS `tickets2014`,
        MONTH(`lastmodified`) AS `month`
    FROM `visitors_2014`
    GROUP BY 
        MONTH(`lastmodified`)

) AS `data2014`
ON (
    `data2013`.`month`=`data2014`.`month`
)

为什么不将(主动使用的)数据存储在同一个表中(更简单)?