Question

我希望在jquery中以AP / PM的格式找到两次之间的差异。

我测试了很多代码，但无法找到任何解决方案。

我的一个代码在这里。

var timeStart = new Date("01/01/2007 " + "05.00 AM").getHours();
var timeStartmin = new Date("01/01/2007 "  + "05.00 AM").getMinutes();
var timeEnd = new Date("01/01/2007 " + "10.30 PM").getHours();
var timeEndmin = new Date("01/01/2007 " + "10.30 PM").getMinutes();

timeStart     =   timeStart+"."+timeStartmin;
timeEnd     =   timeEnd+"."+timeEndmin;

var hourDiff = timeEnd-timeStart;    
alert(hourDiff);

但它不能正常工作。任何机构都可以给我一个建议。

Answer 1

您错误地初始化了日期。这就是你应该这样做的方式：

var timeStart = new Date("01/01/2007 " + "05:00 AM");
var timeEnd = new Date("01/01/2007 " + "10:30 PM");

var diff = (timeEnd - timeStart) / 60000; //dividing by seconds and milliseconds

var minutes = diff % 60;
var hours = (diff - minutes) / 60;

然后，无论你想要什么，都可以使用hours和minutes。

Answer 2

首先Date()将不接受"01/01/2007 " + "05.00 PM"它将在getHours（）和其他地方返回NaN。所以你需要传递

var timeStart = new Date("01/01/2007 " + "05:00:00").getHours();

并执行此操作：

var diffhour     =   parseInt(timeEnd)-parseInt(timeStart);
var diffmin     =   parseInt(timeStartmin)-parseInt(timeEndmin);

var Diff = diffhour+":"+diffmin;    
alert(Diff);

javascript中am / pm格式的两次之间的差异

2 个答案: