假设我的表名“POST”只包含“POST_ID”,我有另一个表名post_meta,它还包含“POST_ID”(作为外键)和另外两列“meta_key”和“meta_value”
我的表结构是
post_ID
1
2
meta_id post_id meta_key meta_value
1 1 suite_size 1000
2 1 suite_number 10
3 2 suite_size 2000
4 2 suite_number 20
我想创建一个像
这样的表post_id suite_size suite_number
1 1000 10
2 2000 20
我该怎么做?
答案 0 :(得分:2)
试试这个:
SELECT pm.post_ID,
SUM(CASE WHEN pm.meta_key = 'suite_size' THEN pm.meta_value ELSE 0 END) as suite_size,
SUM(CASE WHEN pm.meta_key = 'suite_number' THEN pm.meta_value ELSE 0 END) as suite_number
FROM post_meta pm
GROUP BY pm.post_ID;
或强>
如果您想要post_meta表中的所有帖子是否不存在,请使用以下查询
SELECT p.post_ID,
SUM(CASE WHEN pm.meta_key = 'suite_size' THEN pm.meta_value ELSE 0 END) as suite_size,
SUM(CASE WHEN pm.meta_key = 'suite_number' THEN pm.meta_value ELSE 0 END) as suite_number
FROM post p
LEFT JOIN post_meta pm ON p.post_id = pm.post_ID
GROUP BY p.post_ID;
答案 1 :(得分:1)
您需要使用数据透视技术将行显示为列以实现此
select
p.post_ID,
max(case when pm.meta_key = 'suite_size' then pm.meta_value end) as `suite_size`,
max(case when pm.meta_key = 'suite_number' then pm.meta_value end) as `suite_number`
from post p
join post_meta pm on pm.post_id = p.post_ID
group by p.post_ID